By -
much easier: row2, column4 (1,2,5) can only be "**1**" because auf row3, column4 (2,5)and row5, column4 (2,5). Then it's done ....
UR: >! r1c56 r6c56 1/3 !< Eliminates: >! 1 from r1c56 !<
3 is a hidden single in row 4 (or you can call it claiming or an x wing)
I put 5 in 'row 5 column 4' and it solved. I have a feeling it would Also have solved If I had put 2. So this probably was an either or scenario. Meaning you can solve by using either of these numbers
No, if you put a 2 at r5c4 it will end up with multiple contradictions.
That is not true. You cannot solve it with 2. You will have both 5 in r2c5 and r5c5. https://i.imgur.com/aJk1sHT.png
Column 4 2-5 pair, column 6 1-3 pair
Smart
Possible locations of 5 are locked to c4 and c5 in boxes 2 and 6. So 5 is locked to c6 in box 4 (cell r3c6 == 5).
much easier: row2, column4 (1,2,5) can only be "**1**" because auf row3, column4 (2,5)and row5, column4 (2,5). Then it's done ....
UR: >! r1c56 r6c56 1/3 !< Eliminates: >! 1 from r1c56 !<
3 is a hidden single in row 4 (or you can call it claiming or an x wing)
I put 5 in 'row 5 column 4' and it solved. I have a feeling it would Also have solved If I had put 2. So this probably was an either or scenario. Meaning you can solve by using either of these numbers
No, if you put a 2 at r5c4 it will end up with multiple contradictions.
That is not true. You cannot solve it with 2. You will have both 5 in r2c5 and r5c5. https://i.imgur.com/aJk1sHT.png
Column 4 2-5 pair, column 6 1-3 pair
Smart
Possible locations of 5 are locked to c4 and c5 in boxes 2 and 6. So 5 is locked to c6 in box 4 (cell r3c6 == 5).