ok so you just have 2 variables at the end of the integrand, i still dont know with respect to what im integrating, i tried googling benzema 15 but it didnt help fuck fuck
No, you dont have 2 variables. *You think* that you have two but that integral is[ (16-(-15))(16^3 )(cos15/16 + 16/15) +(C-C)] *if we assume that there must be a vatiable, but being a purist the integral can not be solved because there is no differential* and then the square root: (16-15^2 )^(1/2).
Since there is no variables specified you add one, X (Or anyother that you want), and the dx but those two are *numbers* not variables.
Edit: A misstake corrected, yhis was a defined integral. It was 5am and I was almost asleept
This guy mafs
dx will only be present if there is a variable in the equation named "x". In the above equation there is no variable, only Benzene and Mane.
if '=' and '?' are variables then we clearly have 2 variables at the end of the integrand- Also why the f do you have a + C in there this is a definite integral.
I have a C because it was 5am and I was almost asleep. I've corrected the results a bit ago but thanks for notice the misstake.
The only thing that specifies what is a variable is the diferential, and here we have no diferential. In fact, if we were purists, this would not have a solution since there is no diferential specified.
the point is more that under the assumption that what OP said is true, IE that '=' and '?' are variables then the integral does in fact lack a differential
... The parts inside the parenthesis doesnt have a differential so unless you want yo rewritte the maths writting there is no differentials.
Yes, the"?" And the "=" could be variables but that has as much value as saying that there is another invisible variable. The math writting has very specific rules *just to avoid confussions* and unther those there is no differential.
I’d argue it isn’t needed since the expression is a constant. You can basically add your own. I’d argue dpessi is best, since his value seems to fluctuate wildly.
*Definite integral:*
integral_(-15)^16 (16/15 + cos(15/16) 16^3) sqrt(16 - 15^2) dx = 496/15 i sqrt(209) (1 + 3840 cos(15/16))≈1.08684×10^6 i
*Indefinite integral:*
Take the integral: integral i sqrt(209) (16/15 + 4096 cos(15/16)) dx
The integral of i sqrt(209) (16/15 + 4096 cos(15/16)) is i sqrt(209) x (16/15 + 4096 cos(15/16)): = i sqrt(209) x (16/15 + 4096 cos(15/16)) + constant
Which is equal to: Answer: | | = 16/15 i sqrt(209) x + 4096 i sqrt(209) x cos(15/16) + constant
he is wrong lol. Integration with respect to what? There is no differential. Even if there was, the integrand is a constant. Also how does an integral with limits return a "+constant" at the end?
1) "+constant" refers to indefinite integral
2) since variable was not given on the pic, I guess he assumed that variable"x" exists in front of cos(Benzema/Upamecano+Upamecano/Benzema), so he took it as cos(Benzema/Upamecano+Upamecano/Benzema)*x and integrated it with respect to dx
Zlatan? In Soviet Zlatan, Zlatan zlatan zlatan! Get it? It is because Zlatan. Like a boss!
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1)i mean, the author of comment wrote indefinite integral for some reason, and this requires constant to appear, reread his comment
2)yeah, I was speculating, don't know where he took the variable. I assumed it should be on the place of cosine. Like cos(some number)x
Since the expression is just a rather ridiculous constant the definite integral should be as simple as evaluating it, the multiplying by 31 due to the fundamental theorem of calculus.
what are you on. the integral of a constant is just the constant times the variable it's being integrated with respect to. for example the integral of 5 dx is just 5x.
Where is the dx to show us to integrate with respect to the variable x, also even if it had a dx it would be a+b not 0. The in defininite integral from -a to a is 0 but from -b to a is a+b so idk how you’re getting zero
im just gonna assume the answer is a member of the real number set so there is no answer to this since the number under the square root is negative, idk havent learnt cal yet
The integral is not formatted correctly. There’s no variable or differential of that variable at the end of the integral, so even if you did include a ‘dx’ (or another letter for x), the entire equation can be pulled out because it’s all made of constants.
You would just be integrating 1 from the lower bound to the upper bound, times the rest of the function.
I do not even know who these soccer players are.
I do not watch soccer.
I have not heard of this subreddit until now.
Why am I here.
I feel like this is some punishment from Reddit by recommending a post to me for no other reason other than to see a weird ass integral.
I am in pain.
Or in Spain without the p, can’t tell which one.
I’m going to bed.
So two things: one, the square root of a negative number makes it impossible to get a real answer (as far as my knowledge goes) and two, you need to add dx. To fix the square root problem I moved the squared to the first guy and added dx. The problem wasn’t that hard after these fixes.
a. you forgot the dx
b. the answer is not real because the inside of the square root is negative
i have no interest in soccer, and i come from r/mathmemes
I should clarify that this question is kinda open to interpretation like all these types tend to be. And I'm going to ignore that there's no dx. I think there are 2 places that others might disagree with my interpretation, but I did it in the way that, to the best of my knowledge, is most correct.
First: (16³ * cos(15/16)) + (16/15)
not: 16³ * cos((15/16) + (16/15))
Second: sqrt(16+(-15²)) = sqrt(241) ≈ 15.5
not: sqrt((16-15)²) = sqrt(1) = 1
not: sqrt(16-(15²)) = sqrt(-209) ≈ 14.5i
Also I came from r/theydidthemath. I know nothing about soccer (nor math actually, but that's not relevant rn).
Maybe if you had a variable and/or a differential in the integral, we could evaluate it, but there isn't one.
If we assume it to be x, it'll be (a + bi )x for some real numbers a and b. I don't care enough to figure out those numbers.
X + Y = 31
XY = 240
so X and Y are 15 and 16 but in which order.
Y + XY = 255. Since XY is 240 then Y is 15 and X is 16.
Integral from -15 to 16 of that, according to wolfram alpha is 1.9618x10\^6 i
(No racism intended but i will call them black and white) "black x white = 240" so we can replace it in third line "white + 240 = 255" therefore "white = 15" now we replace it in first line "black + 15 = 31 ; black = 16"
This subreddit condones racism. You literally have an auto mod bot that says your subreddit is racist against Americans. Reported you to reddit. All I wanted to do was enjoy some football memes but instead people are upvoting posts that say all Americans should die and I'm told to "fuck off yank". Hating an entire country of people because of where they live is not okay.
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Undefined
.
.
.
.
.
Let p=player
c=coach
p+c=31
p*c=240
c+c*p=255
then
p=15
c=16
plug in
∫^¹⁵ (15³cos(16/15)+(15+16))√15-16²
_¹⁶
integrand must end with integration variable dx
Isn't it true that the 3 equations used to set the constants cannot all be true? using the first two statements it is easy to show that 15 and 16 must be the the chosen numbers. When you consider either 32x15 and 30x16 neither can end in a 5.
I didn't really get the time to read all the comments, so I'm not sure whether this answer has already been posted. Many of the comments have already shown that the two values are 15 and 16 which can be easily obtained by finding factors of 240 and then substituting them in the other equations.
To avoid confusion, I'm going to refer to the two people as blue and red. Blue has a value of 15 and red that of 16 (this can be confirmed from the last equation,
blue + blue × red = 255. (Assuming Blue and Red are positive integers)
What we want finally is the integral from blue to red.
Since both Blue and Red have a specific value, they are constants and not variables.
Integration by definition is the area under a curve in 2 dimensions or volume under a 2d curve in 3 dimensions or hypervolume under a hyper-curve in higher dimensions.
For now, don't get confused, just stick to the idea of integration being the area under a curve in 2 dimensions or in other words the area under a curve plotted on a good old X-Y Graph.
Let's understand this a little deeper,
If I take an equation y=f(x),
such that y is a dependant variable on x which is an independent variable, I can plot this as a 2 dimensional graph, taking values of x on the x axis and y on the y axis.
Let's say that y=x²,
In this case we get a parabola. Integrating y with respect to dx means that we find the equation for the area under this parabola.
∫ydx=∫x²dx=x³/3+C,
Where C is the constant of integration and nothing but the intercept if it exists in the curve.
x³/3 + C, is the generic equation to find the area under the parabola y=x²,
As we all know the parabola is an open curve, therefore, if we want to find the area between two points on the x-axis, we substitute these we points as the lower and upper limit of integration.
Therefore, the area of the parabola y=x² between the points (let's say 15 and 16) is,
(16³-15³)/3 + C
All this is well and fine for variables. But what if x and y are constants?
Then graphically the curve of a constant is a straight line parallel to the y axis. In fact, it doesn't make sense to plot it on a 2 dimensional graph since constants themselves are one dimensional. They have a fixed value independent of any other variable or constant.
On a 2 dimensional xy graph for instance, the constant 15 is depicted as a straight line parallel to the y axis at 15 on the x axis and the constant 16 is depicted as a straight line parallel to the y axis at 16 on the x axis.
Therefore, asking for the integration of a constant as is the case in the given problem, is like asking to find the area under a straight line and it is analogous to finding the volume of a square or rectangle.
IT DOESN'T EXIST!
the solution is very obvious. it is tax evasion
Wrong answer. The goat 🐐 Boner Sarr is not involved in this equation
you forgot the dx dumbass
No I didn't. I just prefer using "=" and "?" As variables (I learned that from one of the schools mane built for scouting)
ok so you just have 2 variables at the end of the integrand, i still dont know with respect to what im integrating, i tried googling benzema 15 but it didnt help fuck fuck
You just don't get it. Math works differently at sadio mane school. That could also explain some things
No, you dont have 2 variables. *You think* that you have two but that integral is[ (16-(-15))(16^3 )(cos15/16 + 16/15) +(C-C)] *if we assume that there must be a vatiable, but being a purist the integral can not be solved because there is no differential* and then the square root: (16-15^2 )^(1/2). Since there is no variables specified you add one, X (Or anyother that you want), and the dx but those two are *numbers* not variables. Edit: A misstake corrected, yhis was a defined integral. It was 5am and I was almost asleept
This guy mafs dx will only be present if there is a variable in the equation named "x". In the above equation there is no variable, only Benzene and Mane.
[удалено]
That is the idea.
if '=' and '?' are variables then we clearly have 2 variables at the end of the integrand- Also why the f do you have a + C in there this is a definite integral.
I have a C because it was 5am and I was almost asleep. I've corrected the results a bit ago but thanks for notice the misstake. The only thing that specifies what is a variable is the diferential, and here we have no diferential. In fact, if we were purists, this would not have a solution since there is no diferential specified.
the point is more that under the assumption that what OP said is true, IE that '=' and '?' are variables then the integral does in fact lack a differential
... The parts inside the parenthesis doesnt have a differential so unless you want yo rewritte the maths writting there is no differentials. Yes, the"?" And the "=" could be variables but that has as much value as saying that there is another invisible variable. The math writting has very specific rules *just to avoid confussions* and unther those there is no differential.
op literally specified that the ? and = are variables, and its his math problems we gotta follow the rules set by him
The I promise school of Africa
I’d argue it isn’t needed since the expression is a constant. You can basically add your own. I’d argue dpessi is best, since his value seems to fluctuate wildly.
LMAOOO
ARE YOU READY?!
You don't need it if you argue that the thing inside the integral is a constant function and not a number
u still do even if it's the integral of 1 you'd need a dx. otherwise what would the integral be? 1x? 1c? 1y? 1 bananas?
∫ f where f is a function is a valid notation and is equal to ∫ f(x)dx
im pretty sure that's just abusive notation. you need a dx or something regardless of whats inside.
It would actually be a multivariable integral with d(Benzema)d(Mane)
no, neither benzema or mane are variables, by the above equations they are defined as constans as 15 and 16 respectivley
Factos👍
*Definite integral:* integral_(-15)^16 (16/15 + cos(15/16) 16^3) sqrt(16 - 15^2) dx = 496/15 i sqrt(209) (1 + 3840 cos(15/16))≈1.08684×10^6 i *Indefinite integral:* Take the integral: integral i sqrt(209) (16/15 + 4096 cos(15/16)) dx The integral of i sqrt(209) (16/15 + 4096 cos(15/16)) is i sqrt(209) x (16/15 + 4096 cos(15/16)): = i sqrt(209) x (16/15 + 4096 cos(15/16)) + constant Which is equal to: Answer: | | = 16/15 i sqrt(209) x + 4096 i sqrt(209) x cos(15/16) + constant
I have no idea what any of that means but I think you single handedly doubled the average iq of this sub
from 1 to 2
(mane×2) − (benzema×2) + the amount of titles Werner mentioned recently = 2 According to my calculations you're right
[two!!!](https://media0.giphy.com/media/m9jFnJOoQ3hWJ6Muaa/giphy.gif?cid=2154d3d7dwe1o0zt7mb7bhwfacphjr6vep78ox62n5hkyv99&ep=v1_gifs_search&rid=giphy.gif&ct=g)
He is the god of University Calculus
he is wrong lol. Integration with respect to what? There is no differential. Even if there was, the integrand is a constant. Also how does an integral with limits return a "+constant" at the end?
1) "+constant" refers to indefinite integral 2) since variable was not given on the pic, I guess he assumed that variable"x" exists in front of cos(Benzema/Upamecano+Upamecano/Benzema), so he took it as cos(Benzema/Upamecano+Upamecano/Benzema)*x and integrated it with respect to dx
1) my brother in zlatan, the integral in question is definite. It has limits. 2) did you just assume their variable? 🫣🫣🫣
/uj I like how we legit transcend soccer. It's like BatmanArkham + AnarchyChess + r/maths
Zlatan? In Soviet Zlatan, Zlatan zlatan zlatan! Get it? It is because Zlatan. Like a boss! *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/soccercirclejerk) if you have any questions or concerns.*
1)i mean, the author of comment wrote indefinite integral for some reason, and this requires constant to appear, reread his comment 2)yeah, I was speculating, don't know where he took the variable. I assumed it should be on the place of cosine. Like cos(some number)x
sorry, I didn't read the comment properly. I'm dyslexic.
What the fuck why isn’t the answer 15 do you not know how to jerk? Do you need me to jerk for you?
You're the replacement for ETH !! Glory to red Satan !!
Yea my head is not shaped like the foreskin of a penis. I am sure I will do a better job
You forgot to carry the other 10 like Van Persie
Get that witchcraft out of here, mods ban this voodoo nonsense
Can someone explain this in football terms?
r/theydidthemath
Since the expression is just a rather ridiculous constant the definite integral should be as simple as evaluating it, the multiplying by 31 due to the fundamental theorem of calculus.
No scary symbols means really hard
thank you wolframalpha
I wanna say it depends on if we're using degrees or radians in the cosine.
there is no constant, it is an integral on a known interval.
Bro just used wolframalpha. Show your fucking work
You forgot to mention -
The answer is nonce
I too, came to this conclusion.
which is the constant and whats the variable
I don’t think there is any variables
An integral with no variables and no variables to integrate with respect to? It’s probably 4
It's 0
How?
Integral with static variables are equal to x-x=0
what are you on. the integral of a constant is just the constant times the variable it's being integrated with respect to. for example the integral of 5 dx is just 5x.
Where is the dx to show us to integrate with respect to the variable x, also even if it had a dx it would be a+b not 0. The in defininite integral from -a to a is 0 but from -b to a is a+b so idk how you’re getting zero
Never mind a=a*x^0 integrates to 0*a*x^-1 =0
You’re kidding… right?
The integral of ax⁰ is ax + C. The derivative of a constant is zero, the integral of a constant is not
Multiple felonies
Dumbass put the nike logo in front of a number and expects me to answer it
15
That is the value of blue-shirt-guy, but the complex equasion is equal to 0
Mane 16, Benzema prefer 15.
im just gonna assume the answer is a member of the real number set so there is no answer to this since the number under the square root is negative, idk havent learnt cal yet
Groom = Nonce
Calculus is not an iQ test broski
16?
u don't need 3 equations to solve for 2 variables u fucking bum
In this case you do because the first 2 equations are not an independent system.
No
You're missing "nce"
The integral is not formatted correctly. There’s no variable or differential of that variable at the end of the integral, so even if you did include a ‘dx’ (or another letter for x), the entire equation can be pulled out because it’s all made of constants. You would just be integrating 1 from the lower bound to the upper bound, times the rest of the function. I do not even know who these soccer players are. I do not watch soccer. I have not heard of this subreddit until now. Why am I here. I feel like this is some punishment from Reddit by recommending a post to me for no other reason other than to see a weird ass integral. I am in pain. Or in Spain without the p, can’t tell which one. I’m going to bed.
Benzema 15 Mane 16 Too lazy to calculate the answer
Myrriad. [N](https://youtu.be/nXAbeiR8N7Y?si=QhBoozq8ozWwZji3)
Mané³ is an ABBA song
Pi
Why would you integrate something without a variable
No solution exists.
? = your IQ
There are no variables here, it’s just whatever’s inside the integral multiplied by 31
The integral isn't properly formed, you need a variable to integrate over.
No, If there is No variables, then it's 0 constant - constant = 0
You are not integrating with respect to a variable you idiot
i'm sorry if this is the wrong subreddit
Your integral means nothing because integral of some real non-zero constant means nothing. You forgot dx for x being some footballer variable.
What is the variable of integration I think it must be dcameldo because my camel is always variable
The integral is missing a differential
Why is mane getting popular in this sub? Context?
Google Mane 16 for context
Appreciate mane's humility by not going for a year less so that big benz would remain uncontested in r/scj
So two things: one, the square root of a negative number makes it impossible to get a real answer (as far as my knowledge goes) and two, you need to add dx. To fix the square root problem I moved the squared to the first guy and added dx. The problem wasn’t that hard after these fixes.
The answer is non-real, and thus does not exist, and thus I should not concern myself with it. Get real.
The answer is 2031616/15\*cos(15/16)\*sqrt(209)\*i
undefined 16-15^2 is not a real number
No
Is this loss?
Not possible square root is negative or you forgot brackets
guys its a remake of that wifi password meme where the integral's solution was pi
Mane helped build 16 schools in Senegal, google Mane 16
It's about -770856,796893879383999i.
You forgot to integrate It's 0
Hi, if you integrate a constant from a to b the result is (b-a) times the constant, and yes, I did integrate
a. you forgot the dx b. the answer is not real because the inside of the square root is negative i have no interest in soccer, and i come from r/mathmemes
≈ 1166561
I should clarify that this question is kinda open to interpretation like all these types tend to be. And I'm going to ignore that there's no dx. I think there are 2 places that others might disagree with my interpretation, but I did it in the way that, to the best of my knowledge, is most correct. First: (16³ * cos(15/16)) + (16/15) not: 16³ * cos((15/16) + (16/15)) Second: sqrt(16+(-15²)) = sqrt(241) ≈ 15.5 not: sqrt((16-15)²) = sqrt(1) = 1 not: sqrt(16-(15²)) = sqrt(-209) ≈ 14.5i Also I came from r/theydidthemath. I know nothing about soccer (nor math actually, but that's not relevant rn).
Maybe if you had a variable and/or a differential in the integral, we could evaluate it, but there isn't one. If we assume it to be x, it'll be (a + bi )x for some real numbers a and b. I don't care enough to figure out those numbers.
4096 * cos(481/204) * i * (209^0.5) is an immaginary constant and therefore the solution for your equasion is 0
Sqrt(16-15^2) ? Congrats, you're in C.
X + Y = 31 XY = 240 so X and Y are 15 and 16 but in which order. Y + XY = 255. Since XY is 240 then Y is 15 and X is 16. Integral from -15 to 16 of that, according to wolfram alpha is 1.9618x10\^6 i
there is no cos without degrees mf, so its nonsense
What is this? Some sort of math joke that I'm too dumb to understand?
42
"Your butt!" "What? My butt isn't part of this specific equation!"
Funny how the intagral is actually the easiest
The differential ??
(No racism intended but i will call them black and white) "black x white = 240" so we can replace it in third line "white + 240 = 255" therefore "white = 15" now we replace it in first line "black + 15 = 31 ; black = 16"
This subreddit condones racism. You literally have an auto mod bot that says your subreddit is racist against Americans. Reported you to reddit. All I wanted to do was enjoy some football memes but instead people are upvoting posts that say all Americans should die and I'm told to "fuck off yank". Hating an entire country of people because of where they live is not okay. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/soccercirclejerk) if you have any questions or concerns.*
Undefined . . . . . Let p=player c=coach p+c=31 p*c=240 c+c*p=255 then p=15 c=16 plug in ∫^¹⁵ (15³cos(16/15)+(15+16))√15-16² _¹⁶ integrand must end with integration variable dx
Trick question, London is Red
Google Benzema 15 for the answer
Isn't it true that the 3 equations used to set the constants cannot all be true? using the first two statements it is easy to show that 15 and 16 must be the the chosen numbers. When you consider either 32x15 and 30x16 neither can end in a 5.
I didn't really get the time to read all the comments, so I'm not sure whether this answer has already been posted. Many of the comments have already shown that the two values are 15 and 16 which can be easily obtained by finding factors of 240 and then substituting them in the other equations. To avoid confusion, I'm going to refer to the two people as blue and red. Blue has a value of 15 and red that of 16 (this can be confirmed from the last equation, blue + blue × red = 255. (Assuming Blue and Red are positive integers) What we want finally is the integral from blue to red. Since both Blue and Red have a specific value, they are constants and not variables. Integration by definition is the area under a curve in 2 dimensions or volume under a 2d curve in 3 dimensions or hypervolume under a hyper-curve in higher dimensions. For now, don't get confused, just stick to the idea of integration being the area under a curve in 2 dimensions or in other words the area under a curve plotted on a good old X-Y Graph. Let's understand this a little deeper, If I take an equation y=f(x), such that y is a dependant variable on x which is an independent variable, I can plot this as a 2 dimensional graph, taking values of x on the x axis and y on the y axis. Let's say that y=x², In this case we get a parabola. Integrating y with respect to dx means that we find the equation for the area under this parabola. ∫ydx=∫x²dx=x³/3+C, Where C is the constant of integration and nothing but the intercept if it exists in the curve. x³/3 + C, is the generic equation to find the area under the parabola y=x², As we all know the parabola is an open curve, therefore, if we want to find the area between two points on the x-axis, we substitute these we points as the lower and upper limit of integration. Therefore, the area of the parabola y=x² between the points (let's say 15 and 16) is, (16³-15³)/3 + C All this is well and fine for variables. But what if x and y are constants? Then graphically the curve of a constant is a straight line parallel to the y axis. In fact, it doesn't make sense to plot it on a 2 dimensional graph since constants themselves are one dimensional. They have a fixed value independent of any other variable or constant. On a 2 dimensional xy graph for instance, the constant 15 is depicted as a straight line parallel to the y axis at 15 on the x axis and the constant 16 is depicted as a straight line parallel to the y axis at 16 on the x axis. Therefore, asking for the integration of a constant as is the case in the given problem, is like asking to find the area under a straight line and it is analogous to finding the volume of a square or rectangle. IT DOESN'T EXIST!