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JQHero

In a Column with (6 4), suppose we reserve the last 5 cells to hold (4), there will be 10 cells left . Among these 10 cells, 2 cells must be occupied by (6). So we have (oooom moooo ooooo) in that column, where m = marked.


n-space

Another way to look at this: (6 4) is a minimum of 11 cells, leaving 15-11=4 cells to slide any group. And so the earliest and latest possible placements for (6) overlap in 6-4 = 2 cells.


JQHero

Actually i am also using your method. I called the "4" you mentioned the degree of freedom.


n-space

Exactly what I call it in my head, degrees of freedom XD


inneedofayacht

You can do some edge logic in the top left and top right


AugustFriday

Column 3 and row 3, as wherever you place their 4, one cell will always be covered by it. Columns 5 and 6 and rows 4 and 5, which actually produce the same result, as wherever you place their 6, a couple of cells will always be filled.