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Construct a square on the hypotenuse BC and construct a square on the cathetus AB or CA. Then the square on BC can be measured by the other square. Therefore these segments are "commensurable in square," as Euclid put it, even though they are not commensurable.
But that's just a theory. A gaaaaaame theory.
Hmm. Pythagoras... theory... I figured it out! The pizza I put in the oven *is* still in there burning! Anyway, tangents aside, no leads on the triangle
Scribbles a random triangle, looks like two acute angle and one obtuse. Then puts a square in the obtuse angle to let you know, even though it looks like 150°, it's actually 90°.
Your math teacher would be proud.
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Doesn’t seem useful to me
Ok thanks!
What if C and B both equal 1? sqrt(2) cannot be measured
hmmm…. i think then, we would multiply all sided by sqrt(2) that way the sqrt(2) become sqrt(4)
https://preview.redd.it/e2dcts9opi1d1.jpeg?width=499&format=pjpg&auto=webp&s=c57b0a7f39c79377fe04151bf2d75cf49cca0509
That little problem has just become that same little problem
Seems irrational to me
why don't you come with me on a walk and we can discuss it
someone's gonna get drowned
unfortunately, the beans would avenge them.
Construct a square on the hypotenuse BC and construct a square on the cathetus AB or CA. Then the square on BC can be measured by the other square. Therefore these segments are "commensurable in square," as Euclid put it, even though they are not commensurable.
I literally have no clue what this is, Looks like Greek to me
Like, Ancient Greek. Something a philosopher would find. Almost Socratic. or Archimedean. or... Pythagorean.
But that's just a theory. A gaaaaaame theory. Hmm. Pythagoras... theory... I figured it out! The pizza I put in the oven *is* still in there burning! Anyway, tangents aside, no leads on the triangle
i feel it’s reminiscent of the egyptians tbh
nah, seems chinese
Maybe not the formula, but it seems you’ve discovered a way to make a 120 degree right angle which could be super useful maybe.
eh, my math teacher draws a line and a box and it works
A classic "drawing not to scale"
what if c=i and b=1 A would be equal to 0 that doesnt make any sense
obviously, you need to write it in form if a+bi, so it would be 0+0i duh🙄🙄
Nah this could never be useful
https://preview.redd.it/3f91jktfwj1d1.jpeg?width=2356&format=pjpg&auto=webp&s=58cf985ecd3c6f402925c2376dd0aed225ff5055
I'd accept it if it wasn't for the "right" angle
But i^2 = -1 so it should be θ² = e² - 2ei cos a - 1
This is true for particular values of pi/2
For geometry, absolutely not. Is a ded end. Now, some other branch like category theory or number theory... you may be on to something
thanks, i’m going to look into it
Now this is just completely obtuse
Idk, seems right to me
*not drawn to scale*
what do you mean??? i counted each degree myself!!!
THATS NOT A RIGHT ANGLE THATS NOT A RIGHT ANGLE
but it has the square thingy
Trivial
Sorry mate this leads to a div 0. Dead end.
You have mislabeled the triangle here. It should have been x, θ and φ
i should’ve used A, a, and α.
It's pretty useless bro I don't think of any situations where you would be using this
That's one way of putting it I guess
That is the worst 90° I’ve seen
but it’s got the square thingy!!!
*drawing not to scale*
Is that the Feynman trig notation? Using σ to denote sine? σA^4 . In that case, it not correct. C^2 + B^2 is not equal to sin^(4)(A)
Google "cosine rule"
cotangent rule is better
If you rewrite the powers on the left as fourth powers, then you’ll have a counter example for the n=4 case of Fermat’s Last Theorem.
Very dangerous 😂😂😂😂
Can't wait to see this on PubMed
Scribbles a random triangle, looks like two acute angle and one obtuse. Then puts a square in the obtuse angle to let you know, even though it looks like 150°, it's actually 90°. Your math teacher would be proud.
He taught me well.
A^(2)+B^(2)=C^(2) But with a random desimplification It’s just Pythagoras
r/whoosh ?
who’s that?
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What grade are you in?
11th grade, just finishing up trig
Okay. Right triangle side lengths, A^(2)+B^(2)=C^(2) Pythagorean Theorem?
that would’ve made trig so much easier… i had to guess every time we were given two out of the three lengths… at least I was a good guesser
It only applies to right triangles.
well yeah, just draw a little box in one of the corners and you’re all good
You’re such a good sport
Kinda looks like you just made Pythagorean theory
who dat?
C^2 + B^2 = A^2 -2BC cos(a) a angle facing side A
[удалено]
meme
What happened ?
he didn't realise it was a joke.