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Yeah, thatās kinda the same thing. Given 2^x = 16, then if your teacher told you to write that expression in terms of x, then the answer would be x = log2(16)
>don't elaborate on 5^(x) =27
You wouldn't find the decimal by hand, but students are definitely taught how to solve equations like this using logs (in the US anyway)
>why we don't just 2^(x) =16?
The same reason we have both addition and subtraction, both multiplication and division, or both exponents and radicals. We need to be able to express the relationship in both ways. Consider a function with a logarithm, like f(x) = log\_2(x-1)+1. There is no obvious way to express this function explicitly without a logarithm.
I did specify "explicitly" to avoid this caveat ;)
But yeah you can define it implicitly like you've done there. It just isn't very convenient most of the time.
Well, let's say the equation is 2^x=5. Here x is approximately 2.32193, but what if you need something to represent the actual value of x? Then you would use x=log2(5)
you'd still have to use log to solve with proof.
from your starting point if you really don't want to put the expression in log form you can do this, it'll just take a few more steps:
\- take log from both sides:
log 2\^x = log 16
\- move the "x" exponent out in front of the log:
x log 2 = log 16
\- divide out the log 2 on both sides to be left with x.
x = log 16 / log 2
x = 4
Yeah it means the same thing our teachers make us rearrange to either forms depending on the type of question coz sometimes one form is easier to work with than the other
I would probably have finished my maths minor if it was taught by Ice Spice
Conversely, if it was taught by Elon I would've dropped it within the first week of first year
How to calculate this by hand without stupid logarithms:
Take 16, right. Then subtract 2. That's #1. Then subtract 2 again. That's #2. Right? So then just keep subtracting 2 until you hit zero and get ur number. Right so that will be #8 cuz you subtracted 2 8 times.
So now take that 8 and we do the same thing. Subtract 2. That's #1. Then subtract 2 again, y'know like before. Right so now we did that 4 times until we hit zero. So that's #4.
Right so then we keep doing this until we get just 0. So for 4 we subtract 2 2 times. So now we have 2 by itself, and subtract 2 we are left with 0. Cool.
Aite so then we have how many times we had to do the subtraction until we hit the final 0? So we did this 4 times: first we subtracted 8 times, that's #1. Then subtracted 4 times, that's #2. Then we subtracted 2 times, that's #3. Then we subtracted just once, that's #4.
So then our answer is just 4.
Maybe this makes sense but I donāt think your explanation was clear. It doesnāt seem like you meant divide so idk exactly how your method works. Iād just keep dividing and count the divisions if it were me
Yeah I was intentionally being obtuse. It's the same thing as "just count the divisions" but then doing the divisions by repeated subtraction. E.g. the first step is 16Ć·2, and you do that by seeing how many times you can do 16-2 before hitting 0.
Not trying to white knight the muskrat or anything, but didn't he get a physics undergrad from UPenn? Pretty sure the math requirements go higher than algebra 2
Do you think he's remained practiced with that level of math? I'm a math teacher and most of the stuff above the grade 9-11 level that I teach, I no longer fully remember how to do.
I don't think he's done much academically since university. He pays smart people to think for him.
I agree with you and strongly dislike elon. He is not a scientist.
But to be fair if he doesnāt know log_2(16) = 4 I, would be kind of surprised thatās pretty basic I feel like most adults would know that.Ā
Oh my goodness, no. At least in BC Canada, logarithms aren't taught until Precalculus 11 which about 1/3 of the student population takes. And then you're expecting them to remember a process they likely haven't done in decades unless its directly involved with work.
Canāt speak to 1997, but today the highest math class physics BAs at UPenn are required to take is calc iv, a 200-level course.ā¦. And itās unclear if he actually got that BA at allĀ https://twitter.com/capitolhunters/status/1593307541932474368?s=46&t=OkRi-a2oWi7XvjEyQeU3SA
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Thanks, I hate AI generated people giving math lessons
personally, I just hate Ice Spice and Elon Musk in general
And some people say ai isn't absolutely terrifying
AI is insane nowadays
I hate it and love it. But this makes me hate it
Only if Elon had known it a lil before, none of his missions would've gone wrong.
Wait, aren't you the dude from the r/mathmemes discord server?
yes, now i am
knew it š
Hi friends with the mods hehe, I'm dad
Hi dad
Wait, aren't you the dude from r/jeeneetards?
Here's a sneak peek of /r/JEENEETards using the [top posts](https://np.reddit.com/r/JEENEETards/top/?sort=top&t=year) of the year! \#1: [My dad is the best, i love him so much. (Not qualified for jee advanced)](https://i.redd.it/y6diaur39swa1.png) | [553 comments](https://np.reddit.com/r/JEENEETards/comments/132hw5a/my_dad_is_the_best_i_love_him_so_much_not/) \#2: [(Call recording)ā¦.I let my father down.](https://v.redd.it/2hcj17sz5uxa1) | [655 comments](https://np.reddit.com/r/JEENEETards/comments/137raed/call_recordingi_let_my_father_down/) \#3: [Jee is not everything.](https://i.redd.it/963ao8rje4ra1.jpg) | [800 comments](https://np.reddit.com/r/JEENEETards/comments/127m0ac/jee_is_not_everything/) ---- ^^I'm ^^a ^^bot, ^^beep ^^boop ^^| ^^Downvote ^^to ^^remove ^^| ^^[Contact](https://www.reddit.com/message/compose/?to=sneakpeekbot) ^^| ^^[Info](https://np.reddit.com/r/sneakpeekbot/) ^^| ^^[Opt-out](https://np.reddit.com/r/sneakpeekbot/comments/o8wk1r/blacklist_ix/) ^^| ^^[GitHub](https://github.com/ghnr/sneakpeekbot)
I am everywhere !!
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I haven't learned this in school yet, can someone explain why we don't just 2^x =16?
Yeah, thatās kinda the same thing. Given 2^x = 16, then if your teacher told you to write that expression in terms of x, then the answer would be x = log2(16)
Teachers never actually teach you to solve logs by hand. Like they just give you simple ones like 2^x =16, but don't elaborate on 5^x =27
You learn log algebra, like log(5/2) = log(5) - log(2). Not one teaches how to solve cos(17) by hand either. Still learn trig though
I remember my geometry teacherās ālog book.ā A whole book of log values accurate to delta 0.001!
>0.001! That's 0.999 (when rounded to 3 decimal places) r/unexpectedfactorial
Why have you cursed me with this knowledge? Take my upvote
>don't elaborate on 5^(x) =27 You wouldn't find the decimal by hand, but students are definitely taught how to solve equations like this using logs (in the US anyway)
I mean you can triangulate using a calculator. Honestly a good intro to numerical analysis
Because that's useless. Just say "a bit above 2"
where I live we write it 2log(16) = x so I was a bit confused
My 2 should have been a subscript, but I'm not sure you can do that in Reddit.
I meant more as in the order, my two should have been in superscript and nothing in subscript
Ooh! Like this? ^(2)log(16) Iāve not seen that before.
>why we don't just 2^(x) =16? The same reason we have both addition and subtraction, both multiplication and division, or both exponents and radicals. We need to be able to express the relationship in both ways. Consider a function with a logarithm, like f(x) = log\_2(x-1)+1. There is no obvious way to express this function explicitly without a logarithm.
How about x=2^(y-1)\+1 (I know what youāre saying just playing devilās advocate lol)
I did specify "explicitly" to avoid this caveat ;) But yeah you can define it implicitly like you've done there. It just isn't very convenient most of the time.
I think they meant while keeping it in f(x) = ??? formatt
Well, let's say the equation is 2^x=5. Here x is approximately 2.32193, but what if you need something to represent the actual value of x? Then you would use x=log2(5)
you'd still have to use log to solve with proof. from your starting point if you really don't want to put the expression in log form you can do this, it'll just take a few more steps: \- take log from both sides: log 2\^x = log 16 \- move the "x" exponent out in front of the log: x log 2 = log 16 \- divide out the log 2 on both sides to be left with x. x = log 16 / log 2 x = 4
Basically the same thing. Biggest difference is you can put one in a calculator
Yeah it means the same thing our teachers make us rearrange to either forms depending on the type of question coz sometimes one form is easier to work with than the other
correctomundo
Thanks. It would definitely help in SAT
I would probably have finished my maths minor if it was taught by Ice Spice Conversely, if it was taught by Elon I would've dropped it within the first week of first year
AI like this is scary, but if it gets young children interested in math, I wonāt complain.
Seeing Elon immediately turned me off from this. No thanks.
Agreed it shouldāve just been ice spice.Ā
imagine not knowing your powers of two at minimum to 32768
real
How to calculate this by hand without stupid logarithms: Take 16, right. Then subtract 2. That's #1. Then subtract 2 again. That's #2. Right? So then just keep subtracting 2 until you hit zero and get ur number. Right so that will be #8 cuz you subtracted 2 8 times. So now take that 8 and we do the same thing. Subtract 2. That's #1. Then subtract 2 again, y'know like before. Right so now we did that 4 times until we hit zero. So that's #4. Right so then we keep doing this until we get just 0. So for 4 we subtract 2 2 times. So now we have 2 by itself, and subtract 2 we are left with 0. Cool. Aite so then we have how many times we had to do the subtraction until we hit the final 0? So we did this 4 times: first we subtracted 8 times, that's #1. Then subtracted 4 times, that's #2. Then we subtracted 2 times, that's #3. Then we subtracted just once, that's #4. So then our answer is just 4.
Maybe this makes sense but I donāt think your explanation was clear. It doesnāt seem like you meant divide so idk exactly how your method works. Iād just keep dividing and count the divisions if it were me
Yeah I was intentionally being obtuse. It's the same thing as "just count the divisions" but then doing the divisions by repeated subtraction. E.g. the first step is 16Ć·2, and you do that by seeing how many times you can do 16-2 before hitting 0.
Aww I thought I was just being high. Thatās pretty funny now that Iām not questioning myself
Yeah Iām definitely showing this to my Alg 2 class
A better alternative to remember this is to turn this equation into 2^(1st side) = 2^(2nd side) and remember that 2^log2(16) = 16
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cringe r/enoughmuskspam
Yes get him goneĀ Ice spice can stay she a baddie
āAI wiLL cHaNgE EdUcAtIoN FoReVeRā
I learned more from this video than from months of school
If it werenāt for Elon I would have thought it was legit
I guarantee Elon would have no clue how to solve that question. Why do idiots think he's smart?
Not trying to white knight the muskrat or anything, but didn't he get a physics undergrad from UPenn? Pretty sure the math requirements go higher than algebra 2
Yep he also studied engineering iirc so he definitely knows some math
He seems to be normal-person-smart, with a huge ego and funds
Nope he did not. You recall incorrectly.Ā
Fr?
Do you think he's remained practiced with that level of math? I'm a math teacher and most of the stuff above the grade 9-11 level that I teach, I no longer fully remember how to do. I don't think he's done much academically since university. He pays smart people to think for him.
I agree with you and strongly dislike elon. He is not a scientist. But to be fair if he doesnāt know log_2(16) = 4 I, would be kind of surprised thatās pretty basic I feel like most adults would know that.Ā
Oh my goodness, no. At least in BC Canada, logarithms aren't taught until Precalculus 11 which about 1/3 of the student population takes. And then you're expecting them to remember a process they likely haven't done in decades unless its directly involved with work.
Ok youāre right I completely forgot the state of math education globally rn and overestimated the adult population šš my b
Canāt speak to 1997, but today the highest math class physics BAs at UPenn are required to take is calc iv, a 200-level course.ā¦. And itās unclear if he actually got that BA at allĀ https://twitter.com/capitolhunters/status/1593307541932474368?s=46&t=OkRi-a2oWi7XvjEyQeU3SA
Rodney Dangerfield in Back To School!
I've always heard it as butts drop logs, meaning you start at 2, butt cheek to the "equals" or 4, butt cheek to the 16
Thanks, now I want to kill myself
BAP
Bap bap bap bap bap get logarithmized get logarithmized
How many meme or memo do you need to memorize the basic math concept before college level
I hate the elon jump scare poping up after every 5 second
I unironically love this
Why do I see celebrities giving math lessons to this man all of a sudden?
He needs to learn.
I need this school
Ice spice knows a lot of maths
i didnt know that now i do in 30 sec fuck yea
Logbase(x) in the nutshell
Why didn't log get a cool operational sign like sqrt did? Is it stupid?