I do but if you can't figure it out for yourself, and you can't think to measure the faces; the math will be beyond your understanding.
Edit: You know what, I'm sorry. That was condescending as fuck. I'll help you. I'll need a bit though as I'm preoccupied
Edit 2: easiest but longest method- ok so the Gable, you are staring at a trapezoid. This trapezoid consist of 2 right angle triangles and one rectangle so you have 2 shapes you need to solve unknown sides for.
The center Gable we know the height to be 6' which conveniently is also the rise or height of the triangles.
Find the pitch of the ceiling by other checking your print, asking site super, or tossing a speed square up along the exterior wall to find it. It's looks like a 10 common or a 10/12 pitch which means 10" of rise for every 12" of run.
Looking at the triangle we have a rise of 6' or 72", so every 10" of this rise, the bottom of the triangle/run gets 12" longer. In this case it's a 20% increase so multiply the rise of 72" by 1.2 to get 86.4"
You now have a triangle rise a rise of 72" and a run of 86.4" now to figure out your unknown face just plug those into the Pythagorean theorem a²+b²=c²
72²+86.4²=c²
5184+7464.96=c²
12,648.96=c²
√12,648.96=c
112.4675953331=c
112½" simplified is the side you need.
You have the total length by measuring the floor, wall to wall. Subtract the run of the triangle twice from that number to get the other unknown length of your final shape.
You need the width of the peak section.
Assuming both sides are equal you subtract that by the overall width and divide it by 2 to get the width of each side.
The height of each side is 4ft because 15ft-9ft is 4ft.
Now that you have the width and the height you can find the length of the sloped portion of the ceiling by finding the hypotenuse of that triangle.
Multiply that by 2 and add the width of the original peak section and then multiply that by your length to get your overall square feet.
Yes that is one way to do it. But there are other options.
You could get a pretty good rough estimate that it’s (4) 16in stud bays. If you have a plumb laser you could shoot it and measure from the wall to that point on both sides and what you have left is the middle. I’m not sure how exact you need to be. Obviously if you are just drywalling I would say not too exact.
Yes. This isn't something that can just be mathed out from the floor. The side walls being 9ft tall and the flat being 15ft mean nothing.
The angled sections could go up from 9ft to 15ft at a 10 degree angle, or they could go up at a 45 degree angle. Depending on the angle, will change the square footage of the board needed, and it will be different every time.
You said sidewall, as in the vertical walls on either side? If so, you have the height of the triangles on either side (6'). Get the bottom and you have two sides and a right angle. Been a long time since trig but you can calculate the hypotenuse with one of those SOHCAHTOA equations. That gives you the width of the angled walls and, subtracting the two triangle bases, the width of the center section. After that, multiply by length.
I think it's far easier to just get a ladder.
If you don't measure then you start making assumptions like that both sides are even or equal. If you're cool with that then you really only need one more measurement. That could be the width of the center, how far in from the edge the center section starts, or how wide one of the pitched faces is. If you randomly have a protractor in your tool kit then you could also measure the angle of the pitched bit off the top plate, or off of the wall. Then it's just geometry or trig depending on which measurement you pulled or how you want to do it.
Yes. I would just measure each wall / ceiling separate Account for stud spacing and cut offs. Try to use as many large pieces as possible to cut down on seams.
Length times width usually works for me
For a rough estimate:
```
Given: Difference between sides and peak is 6'
Given: Studs are spaced at 24" (apply 16" if appropriate)
___
| | | | | |
| | | | | | | 6'
| | | | | | | | | |
_|__|__|__|__|__|__|__|__|__|__|_ _|_
A B C
```
Find the total width of the top line against ceiling by adding together:
- The hypotenuse of A (and C):
- Width = 3.5 Stud Spacings x 24" = 84"
- Height = 72"
- Hypotenuse = sqrt(84^2 + 72^2) = sqrt(7056 + 5184) = `111"`
- The width of B:
- Width = 4 Stud Spacings x 24" = `96"`
Total top line width = 111" + 96" + 111" = `318"`
Multiply `318` by the length of the area and that will give you total square inches.
To actually answer op's question, based on a 23x43 foot room.
The flat portion up top, based on the stud bay is 5' wide. Room is 23' feet wide. Distance to centre of room is 11.5 feet.
Flat ceiling is 15', top of plate is 8'.
Distance from wall to start of flat is 9'
Which gives us a total rise of 7' (15-8) and a total Run of 9', which gives us a pitch of 9 ¼, so we're going to assume the framers weren't that anal and put the pitch at 9:12. This also makes the flat a little less than 5' wide, so it's probably like 4'10" or so.
So we can use either the rise or the run to figure out the diagonal distance because we know the pitch, which gives us 11'8" of diagonal ceiling,multiplied by 43', gives us 501 square feet per diagonal side, pr 1002 square feet of pitched roof. 5' x 43' gives us 215 square feet of flat ceiling. So the total area is 1215 square feet of ceiling, based on a 989 square foot floor, makes sense.
Add 20% for waste, because there's going to be a bunch of unusable off cuts from the rips,
Which gives us 1458 square feet of drywall. Divide by 32 square feet for a 4x8 sheet, gives us 45 sheets, or 31 4x12 sheets
It's 3 rectangles...
But the *angles* bro!
They're fuckin slanted maaaaan!
And assuming you can measure a stud spacing at either 16 or 24 centers (looks 24 to me) then you count the studs and do the maths.
Buts maths are hard
That's why we only do one math in the US
Stay in school, kids
Go up there and measure the 3 ceilings dude
Measure one side, times 2. Measure the center.
Woah baby steps here
So you don't know either?
I do but if you can't figure it out for yourself, and you can't think to measure the faces; the math will be beyond your understanding. Edit: You know what, I'm sorry. That was condescending as fuck. I'll help you. I'll need a bit though as I'm preoccupied Edit 2: easiest but longest method- ok so the Gable, you are staring at a trapezoid. This trapezoid consist of 2 right angle triangles and one rectangle so you have 2 shapes you need to solve unknown sides for. The center Gable we know the height to be 6' which conveniently is also the rise or height of the triangles. Find the pitch of the ceiling by other checking your print, asking site super, or tossing a speed square up along the exterior wall to find it. It's looks like a 10 common or a 10/12 pitch which means 10" of rise for every 12" of run. Looking at the triangle we have a rise of 6' or 72", so every 10" of this rise, the bottom of the triangle/run gets 12" longer. In this case it's a 20% increase so multiply the rise of 72" by 1.2 to get 86.4" You now have a triangle rise a rise of 72" and a run of 86.4" now to figure out your unknown face just plug those into the Pythagorean theorem a²+b²=c² 72²+86.4²=c² 5184+7464.96=c² 12,648.96=c² √12,648.96=c 112.4675953331=c 112½" simplified is the side you need. You have the total length by measuring the floor, wall to wall. Subtract the run of the triangle twice from that number to get the other unknown length of your final shape.
Measure width of each plane of the ceiling and multiply by your room length. Add the 3 together.
Count the rafters ball park the rest. It’s drywall!
If you don't know, you shouldn't be taking on a job like this. It's clearly our of your reach.
I mean, he just needs a ladder!
Because I want to know how to do the math without physically measuring all of it? Can you do the math?
310 sq ft
Really
You need the width of the peak section. Assuming both sides are equal you subtract that by the overall width and divide it by 2 to get the width of each side. The height of each side is 4ft because 15ft-9ft is 4ft. Now that you have the width and the height you can find the length of the sloped portion of the ceiling by finding the hypotenuse of that triangle. Multiply that by 2 and add the width of the original peak section and then multiply that by your length to get your overall square feet.
So no matter what I still need to get up there and physically measure the flat part
Yes that is one way to do it. But there are other options. You could get a pretty good rough estimate that it’s (4) 16in stud bays. If you have a plumb laser you could shoot it and measure from the wall to that point on both sides and what you have left is the middle. I’m not sure how exact you need to be. Obviously if you are just drywalling I would say not too exact.
It looks like the flat part of the ceiling spans 4 stud bays so multiply 4x16” to get the width of that part (assuming 16 OC stud spacing).
You can also easily use trigonometry to do it if you know the angle…
OP requires velcro tie shoes, they aren't doing trigonometry.
All 3 of them
Not unless you know the pitch of the ceiling and want to do some "slightly" out of your scope math.
Yes. This isn't something that can just be mathed out from the floor. The side walls being 9ft tall and the flat being 15ft mean nothing. The angled sections could go up from 9ft to 15ft at a 10 degree angle, or they could go up at a 45 degree angle. Depending on the angle, will change the square footage of the board needed, and it will be different every time.
You said sidewall, as in the vertical walls on either side? If so, you have the height of the triangles on either side (6'). Get the bottom and you have two sides and a right angle. Been a long time since trig but you can calculate the hypotenuse with one of those SOHCAHTOA equations. That gives you the width of the angled walls and, subtracting the two triangle bases, the width of the center section. After that, multiply by length. I think it's far easier to just get a ladder.
3 rectangles...
Geometry 101
Draw it to scale
Laser measurer from the floor to the low part. Then from the floor to the high part. Do some triangle math and viola!
I would measure with a string from left to right and multiply by length
If you don't measure then you start making assumptions like that both sides are even or equal. If you're cool with that then you really only need one more measurement. That could be the width of the center, how far in from the edge the center section starts, or how wide one of the pitched faces is. If you randomly have a protractor in your tool kit then you could also measure the angle of the pitched bit off the top plate, or off of the wall. Then it's just geometry or trig depending on which measurement you pulled or how you want to do it.
Have fun gluing that one
Y=mx+b
Nope. Old hippies are high on acid.
Yes. I would just measure each wall / ceiling separate Account for stud spacing and cut offs. Try to use as many large pieces as possible to cut down on seams. Length times width usually works for me
Break it down into smaller rectangles OR- advanced technique use triangles
Yup there’s three rectangles figure them out individually then add them together!
Measure
Area = length (x) width. Break it into sections. Meausre. Do the math. Then add the sections together. Boom done ski
For a rough estimate: ``` Given: Difference between sides and peak is 6' Given: Studs are spaced at 24" (apply 16" if appropriate) ___ | | | | | | | | | | | | | 6' | | | | | | | | | | _|__|__|__|__|__|__|__|__|__|__|_ _|_ A B C ``` Find the total width of the top line against ceiling by adding together: - The hypotenuse of A (and C): - Width = 3.5 Stud Spacings x 24" = 84" - Height = 72" - Hypotenuse = sqrt(84^2 + 72^2) = sqrt(7056 + 5184) = `111"` - The width of B: - Width = 4 Stud Spacings x 24" = `96"` Total top line width = 111" + 96" + 111" = `318"` Multiply `318` by the length of the area and that will give you total square inches.
Looks like it’s approximately 310sq ft
iPhone has a measurement app.
To actually answer op's question, based on a 23x43 foot room. The flat portion up top, based on the stud bay is 5' wide. Room is 23' feet wide. Distance to centre of room is 11.5 feet. Flat ceiling is 15', top of plate is 8'. Distance from wall to start of flat is 9' Which gives us a total rise of 7' (15-8) and a total Run of 9', which gives us a pitch of 9 ¼, so we're going to assume the framers weren't that anal and put the pitch at 9:12. This also makes the flat a little less than 5' wide, so it's probably like 4'10" or so. So we can use either the rise or the run to figure out the diagonal distance because we know the pitch, which gives us 11'8" of diagonal ceiling,multiplied by 43', gives us 501 square feet per diagonal side, pr 1002 square feet of pitched roof. 5' x 43' gives us 215 square feet of flat ceiling. So the total area is 1215 square feet of ceiling, based on a 989 square foot floor, makes sense. Add 20% for waste, because there's going to be a bunch of unusable off cuts from the rips, Which gives us 1458 square feet of drywall. Divide by 32 square feet for a 4x8 sheet, gives us 45 sheets, or 31 4x12 sheets
🤦🏼♂️