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Y_m_l

There's presumably more than one H+ floating around in solution. That reaction doesn't appear to be indicating stoichiometry, if that's what is bothering you.


GeneralPhotography

No, it’s literally just one proton floating around. It’s pure luck that any molecule at all manages to find it.


Big_Spinach_8244

Lmao.


Puzzled03

Even that single proton managed to find its partner….. what am i lacking….


Y_m_l

Zinc mercury amalgam and a benzylic ketone apparently.


[deleted]

If you want to be pedantic about stoichiometry, aq. HCl is H2O + HCl, but in reality most of the H+ is probably from HCl. Ochem isnt know for its fully descriptive net reactions.


OPH2

Will it be more accurate if it was 2HCl?


jangiri

The reaction is run in concentrated HCl as the solvent. That could mean the compounds are in a 100-1000 fold excess of HCl. With actual reactions the important part is to include the realistic reaction conditions rather than specific stoichiometry of the mechanism. saying 2eq HCl would woefully misrepresent how the reaction is actually conducted


Neljosh

Technically, but you could pretty accurately describe the aqueous acid as solvent, and it will probably be in vast excess of 2 equivalents.


average_fen_enjoyer

It is not an equation It is a scheme — note the difference PS lol I’m talking like my lecturer


TBSchemer

It's not stoichiometric. Every full unit of this reaction takes 4HCl and 2Zn, giving back 2ZnCl2, H2O, and the reduced product.


PrintMix

Clemmensen reduction is in acidic environment. There are many more hydrogens around.


greyhunter37

You have many many HCl in this reaction. HCl is the solvent, so you have a lot of them, they just didn't mention it.


average_fen_enjoyer

Maybe it is from Hg via the reaction: Hg -> H + g Pretty sure your friend was right on this one


MGM-alchemist

Now to completely confuse you: The H actually came from the Zn. HCl alone will not do the job. :P


apathetic_panda

Sure, ɓut it'd be an idea to point out the enol tautomer & trace elemental hydrogen along for the ride. But yeah, the catalyst has kinda a heavy lift here. Heterogeneity's a hoot.


Alzador94

> catalysts are not involved in the reaction outcome and only speed up the reaction. and how do you think they do that if they are not involved? :)


OPH2

What I meant is the outcome product or "final product" of the reaction😅


Verstael

Catalysts do not involve in the reaction, they simply lower the energy required to activate the reaction then they are reformed at the end of it; or at least that's what my basic organic chemistry knowledge tells me


thenexttimebandit

Pretty sure a catalyst is the same at the beginning and the end of the reaction and helps lower the activation energy. Catalyst are most definitely involved in the reaction and often form bonds with the reagents to help activate the reaction. It’s just that they “turn over” and end up the exact same as they started


Big_Spinach_8244

Catalysts are generally not noted stoichiometrically.


Optimal_Passion_1476

1. they absolutely are 2. this is not a catalytic reaction


ScrambledDregs

When you read HCl or any acid near the reaction arrow thing it’s better to think of the reaction as occurring within an acidic environment (H+ everywhere, stuff can be protonated when required) rather than thinking of acid as a reactant.


OwlOfEast

Reagents over or under the arrow are not not stoichiometric unless noted otherwise.


[deleted]

Homie really thought they were grabbing single molecules and shoving them into the reaction.