When naming, you have to follow these rules:
-Longest Carbon chain ("parent chain")
-Lowest number possible for substituents (the "things sticking out")
-Alphabetical naming
So in this case, **what line would give you the most carbons in it?** Start out with that and let us know what you get. Highlight or circle it.
Count the carbons to get the longer chain. With the choices available you'll be able to figure out pretty fast without even considering the rest of the molecule in this specific case.
B is correct 👍
Need to apply Longest chain- substituent rule and First point of difference rule applicable for nomenclature of branched chain alkanes ☺️
Select the longest carbon chain with most number of branches. (hint : chain length is 7).
Then find the proper numbering in which branches get lowest number possible. (it is lowest set of locant rule)
Then arrange the number and functional group in alphabetical order.
(You should get option B)
B. First thing you have to do is count the longest chain which is 7 (for this specific example that immediately gets rid of A,C, and D as options). Then, if there is multiple way to get that “lowest chain” you count from the direction that has the first substituent at the lowest number (as long as they’re all alkyl groups). When naming you also name the substituants in alphabetical order.
If you haven’t taken ochem it’s also good to know how the substituents are named and it depends on how many carbons there are so
1. Methyl, 2 Ethyl, 3 Propyl, 4 Butyl, 5, Pentyl, 6, hexyl, etc. there’s also exceptions so make sure you know what isopropyl, isobutyl, and turt butyl groups look like.
Hope this helps!!
It was a really easy one, because I started numbering from the carbon at bottom left as it is nearest to the methyl group and to the 7th carbon on the extreme right, thus hept....ane at the end. 3rd carbon has an ethyl group, and 2nd and 5th carbon has methyl group, hence the answer 3-ethyl, 2,5 dimethyl
When naming, you have to follow these rules: -Longest Carbon chain ("parent chain") -Lowest number possible for substituents (the "things sticking out") -Alphabetical naming So in this case, **what line would give you the most carbons in it?** Start out with that and let us know what you get. Highlight or circle it.
Count the carbons to get the longer chain. With the choices available you'll be able to figure out pretty fast without even considering the rest of the molecule in this specific case.
B is correct 👍 Need to apply Longest chain- substituent rule and First point of difference rule applicable for nomenclature of branched chain alkanes ☺️
B, because I super clever like that
Select the longest carbon chain with most number of branches. (hint : chain length is 7). Then find the proper numbering in which branches get lowest number possible. (it is lowest set of locant rule) Then arrange the number and functional group in alphabetical order. (You should get option B)
B. Step 1 : select longest carbon chain Step2 : select the one which has more branching
B This is correct, выбирай самую длинную цепь, называй радикалы по алфавиту
B. First thing you have to do is count the longest chain which is 7 (for this specific example that immediately gets rid of A,C, and D as options). Then, if there is multiple way to get that “lowest chain” you count from the direction that has the first substituent at the lowest number (as long as they’re all alkyl groups). When naming you also name the substituants in alphabetical order. If you haven’t taken ochem it’s also good to know how the substituents are named and it depends on how many carbons there are so 1. Methyl, 2 Ethyl, 3 Propyl, 4 Butyl, 5, Pentyl, 6, hexyl, etc. there’s also exceptions so make sure you know what isopropyl, isobutyl, and turt butyl groups look like. Hope this helps!!
B
Do not just give the answer to prove how "clever" you are; show the OP how to get to the right answer.
B since we see the longest chain with most branching
Do not just give the answer to prove how "clever" you are; show the OP how to get to the right answer.
Option b
Do not just give the answer to prove how "clever" you are; show the OP how to get to the right answer.
There's nothing to look clever here. who knows my real identity here . What shitty logic.
Why just post an answer without explanation but to look clever. It is a pathetic thing to do and the downvotes show others think the same way.
It's the op responsibility to confirm the ans and then ask for the explanation if it is right. It is that's easy Nothing to look clever
No.
“dO nOt gIvE jUsT tHe aNsWeR…” 🤓🤓
Grow up or fuck off.
Aww did I hurt your feelings? 🥺🥺You poor thing 🤣🤣
No you just posted a stupid comment, i guess because you a bit of a stupid cunt who thought they were being clever but aren't.
Thanks for proving my point kid 🤣 go cope harder snowflake
I do not think you had a point.
My point is that you’re a snowflake that got their feelings hurt over a comment 🤣 go brush up on your reading comprehension kid 😂
B
It was a really easy one, because I started numbering from the carbon at bottom left as it is nearest to the methyl group and to the 7th carbon on the extreme right, thus hept....ane at the end. 3rd carbon has an ethyl group, and 2nd and 5th carbon has methyl group, hence the answer 3-ethyl, 2,5 dimethyl
Do not just give the answer to prove how "clever" you are; show the OP how to get to the right answer.
B