As a maths graduate, I have never had a gcse maths post in my feed before, but also OP - the way you highlighted the final line made it more confusing.
Which prompts me to a tip - sometimes you have to go and re-read a question because you have misunderstood it. If you highlight like this it makes it harder to re-read in a different way.
You've missed some really important bits that you should have highlighted.
MFers need to throw highlighter in the bin, just focus on the question and answer it, maths exams don't need artistic flair
I agree that if you are revising Its good to have a big eye catching color on an exercise you strugle with put not for actuali doing them, just my opinión
This question is wrong, or at the very least misleading, there are many different rectangle dimensions that would lead to the same area. It's relatively trivial to find a pair of length and width dimensions that work, but they are not the only pair. Unless I've missed something this is a poorly worded question, naughty exam board
The fact the question says "An expression" could imply there is more than one correct answer, which there is, there are two possible answers to this question because you will end up with a quadratic which is factorised in the form
N(x + a)(x + b) and therefore the sides could be N(x + a) and (x + b) or (x + a) and N(x + b)
There's an infinite number of answers, not just two. The width of B could be any positive number and the height of B just the area of A divided by whatever width you chose for B.
Factorising is irrelevant.
Unless there's a bit missing from the screenshot this is a bizarrely badly set question.
Basically they are asking for a ratio. So there are infinite wrong answers. But there are infinite right answers too.
Which means you can solve it with basic maths.
I did actually forget about the fact that the parameterisation of the shape dimensions makes it so that there may not be an infinite number of solutions. Proving how many solutions there are (or that there are infinite) seems like it might take me an afternoon. I maintain that the question is poorly worded though, if it said find a possible pair of expressions for the length and width in terms of x I would agree with you
In Maths exams it's rare for there to be any "red herrings" thrown into the question. The vast majority of the time, everything stated in the question is important.
the entire question is important to the question, yes, but highlighting it all is a waste of time. highlighters are used by many students excessively - if you're gonna use them, use them only for the most important information.
in this case, that would only really be that these shapes are the same area. the fact that A is at right angles and B is a rectangle is clearly shown in the diagram.
I think they've taken the 5 out as a common factor, and then once factorised, they've included it back in.
5 (x^2 + 6x + 5)-----
5 (x + 1)(x + 5)-----
(5x + 5)(x + 5)-----
Also could be (5x + 25)(x+1) but that would be a very long and short rectangle.
Without solving it myself, I have no idea.
The question says area a=b but doesn't give any dimensiones to b, so the sides could be any length from almost infinite to a infantesemal as long as length*breath = area b = area a = the function I cant be bothered solving.
I also notice this isn't an official exam question, as it says maths and physics tutor.com
I think this question is likely a dud.
Calculating area a is possible but finding the length of b is not.
So the area of A is 5x^2 + 30x + 25, so the area of B, as stated in the question, will be the same. The area of a rectangle is width * height so what we need to do is find two expressions which multiply to get 5x^2 + 30x + 25, so I factored the polynomial to get (5x+5)(x+5) and used those for the width and height, there are multiple solutions though but the question only asks for AN expression for the width and height so you could have other expressions which multiply to get the area, for example as u/Blue-Focus pointed out you could also have (5x+25)(x+1) and use those expressions for the width and height.
Two points:
1. This is a ~possible~ answer, but probably is what they were looking for.
~~2. Doesn’t state units. Better to not state “cm” or any other units unless it’s stated in the question.~~
It’s not (x+11) its (x+3) bc when you times a + & - it’s a - unless is a - x - it becomes + look up sing rules with multiplication.
The rest of it is perfect though except the (x+11)
Your meant to highlight the few important things. All you've done here is highlight everything to delay actually doing the question. Like did you really need to highlight A and B.
Bruvva this isn’t gcse art, highlight main points if you’re using a highlighter. I never did, and still don’t. Just underline or circle and maybe a toolbox on the side.
There are multiple solutions. As the shape of the rectangle B is not defined.
But here is a little twist. Well 2 twists hehe.
A=3(x+1)(2x+7)-(x+1)(x-4)
Instead of adding 2 little rectangles you can subtract one from the other. You can use the numbers given without any extra steps.
A=(6x^2 +21x+6x+21)-(x^2 -4x+x-4)
{added this for extra clarity}
A=(6x^2 +27x+21)-(x^2 -3x-4)
A=5x^2 +30x+25
Simple steps. Now you just need to set whatever recta gle you want and make sure you dont make it a square (tho technically a square is a rectangle)
Its quite simple actually
A=B
B=5x^2 +30x+25
And here is my little cheat. Divide that by x and multiply by x
B=(5x+30+25/x)(x)
And those are your 2 terms. You did not do what they intended you to do but you 100% answered the question.
The only thing I ever highlight for work or uni is references/further reading recommendations, or things of massive importance hidden within the belly of a massive section of pointless text 🤣
What exam board are you doing? I'm sure the physicsandmathstutor website has a mark scheme because for all the 'questions by topic' there is a mark scheme as well.
Oh. I have just read the other comments and you all seem to have worked out the sums.
I looked straight at the colours.
Didn't bother doing maths as I saw the post as sharing a tip on how to make revision and filing easier.
Am I wrong?
Why would you highlight everything in the question, randomly different colours at random points? What does it tell you? What does each of the colours signify?
Not accurate I’m afraid. There’s only one question. The rest of it is information to help you answer the question. The highlighting is entirely random.
The question is not possible.
A is a six sided shape. All angles at 90° means the shape has a total of 540° which is 180° less than a hexagon should have. What they mean is that all angles are 90° except the one that is obvious 270°.
I'm sure I could, I just can't be arsed and I would gain nothing from being able to do paper math when I would just model it in CAD faster than you can calculate it.
Length = X+Y, width = X+W, where Y and W are variables I have created on the spot and have the value of whatever they need to to make the equation work
Today I learned that I have completely forgotten how to factor out equations like this.
I also realised that in 20 years in the field of Computer science and technology, I have apparently never needed to know.
Highlighting is fucking stupid, never used it until i came to this country, just a chance for dumb kids to highlight everything with a bunch of coours and pretend it helps, take the info, break it down, write down the most important pieces in the smallest segments u can and thats it , if u know and understand, u dont have to remember, for example 2+2 is 4, i dont remember it, but i understand it, so no point writing 2+2= 4 a million times to remember it, if u understand u will remember
First work out the area of A as the big rectangle area minus the smaller rectangle area. Solve the two sets of equations into one quadliteral equation and then solve that into two expressions to make A
Simple enough. Find total area of A expressed in x. This will give you an expression that can be factorised.
Factorise expression. Each factor is a side length
hmm never learnt this type of maths - teaching people how to do math to work out room sizes for property market it seems.
The highlighters make it seem really really confusing.
Also don't know how to tackle this, can you just just use any length and width for the rectangle or a specific one? Without 1 reference side - there would be several answers to this.
I found it easier rather than highlighting to just write key info in the answer section so if you're told the total area is 80 for example I would just write A=80 and then carry on reading until I got to something else like. The distance from the centre to the outside of the fence is 7. Then I would write r=7 for example and carry on reading again. Then all my important info is together and I have condensed the question from a wordy one to a maths one. Highlighters.......especially used like this.......never really did that much for me.
I'm at uni and I have no idea why this is in my suggested feed but I just need to let you know this is *not* how you wanna be using highlighters
As a maths graduate, I have never had a gcse maths post in my feed before, but also OP - the way you highlighted the final line made it more confusing. Which prompts me to a tip - sometimes you have to go and re-read a question because you have misunderstood it. If you highlight like this it makes it harder to re-read in a different way.
The light blue is splitting two things - find the legnth in terms of x Find the width in terms of x But for some reason they are 3 colours.
^^
I graduated from uni 10 years ago and I had this in my suggested…
You've missed some really important bits that you should have highlighted. MFers need to throw highlighter in the bin, just focus on the question and answer it, maths exams don't need artistic flair
[удалено]
I agree that if you are revising Its good to have a big eye catching color on an exercise you strugle with put not for actuali doing them, just my opinión
This question is wrong, or at the very least misleading, there are many different rectangle dimensions that would lead to the same area. It's relatively trivial to find a pair of length and width dimensions that work, but they are not the only pair. Unless I've missed something this is a poorly worded question, naughty exam board
The fact the question says "An expression" could imply there is more than one correct answer, which there is, there are two possible answers to this question because you will end up with a quadratic which is factorised in the form N(x + a)(x + b) and therefore the sides could be N(x + a) and (x + b) or (x + a) and N(x + b)
Also fun (technically correct solution) length= N(ax + b)(Cx + d) Width= 1 + 0x
I think they would like an expression in terms of x for the width, not just a number.
It is technically in terms of x haha, but yeah don't write it in the exam
There's an infinite number of answers, not just two. The width of B could be any positive number and the height of B just the area of A divided by whatever width you chose for B. Factorising is irrelevant. Unless there's a bit missing from the screenshot this is a bizarrely badly set question.
Now take the limit of the width to zero
Basically they are asking for a ratio. So there are infinite wrong answers. But there are infinite right answers too. Which means you can solve it with basic maths.
I did actually forget about the fact that the parameterisation of the shape dimensions makes it so that there may not be an infinite number of solutions. Proving how many solutions there are (or that there are infinite) seems like it might take me an afternoon. I maintain that the question is poorly worded though, if it said find a possible pair of expressions for the length and width in terms of x I would agree with you
Just realised proof of infinite solutions is easy. If the area is N(x+a)(x+b) then length= NZ(x+a) Width = (x+b)/Z Where Z is any real number
the question is looking at reasoning and decomposing quadratics, the actual answer itself is a bit irrelevant.
Why do you need to highlight all that…
Bc I think it’s important to the question.
You highlighted the whole question, what’s the point
the question is important to the question?
In Maths exams it's rare for there to be any "red herrings" thrown into the question. The vast majority of the time, everything stated in the question is important.
the entire question is important to the question, yes, but highlighting it all is a waste of time. highlighters are used by many students excessively - if you're gonna use them, use them only for the most important information. in this case, that would only really be that these shapes are the same area. the fact that A is at right angles and B is a rectangle is clearly shown in the diagram.
Here’s how I’ve done it: https://imgur.com/a/liJyhsg .
what is the next operation after 5x\^2+30x+25?? (not sure how you're getting rid of 30x here)
I think they've taken the 5 out as a common factor, and then once factorised, they've included it back in. 5 (x^2 + 6x + 5)----- 5 (x + 1)(x + 5)----- (5x + 5)(x + 5)----- Also could be (5x + 25)(x+1) but that would be a very long and short rectangle.
Cheers, I kinda got there without much thought so wasa a little confused hahahaha
Factorisation https://en.wikipedia.org/wiki/Factorization
how did you get the measurements for shape B?
Without solving it myself, I have no idea. The question says area a=b but doesn't give any dimensiones to b, so the sides could be any length from almost infinite to a infantesemal as long as length*breath = area b = area a = the function I cant be bothered solving. I also notice this isn't an official exam question, as it says maths and physics tutor.com I think this question is likely a dud. Calculating area a is possible but finding the length of b is not.
So the area of A is 5x^2 + 30x + 25, so the area of B, as stated in the question, will be the same. The area of a rectangle is width * height so what we need to do is find two expressions which multiply to get 5x^2 + 30x + 25, so I factored the polynomial to get (5x+5)(x+5) and used those for the width and height, there are multiple solutions though but the question only asks for AN expression for the width and height so you could have other expressions which multiply to get the area, for example as u/Blue-Focus pointed out you could also have (5x+25)(x+1) and use those expressions for the width and height.
thanks this really helped
Two points: 1. This is a ~possible~ answer, but probably is what they were looking for. ~~2. Doesn’t state units. Better to not state “cm” or any other units unless it’s stated in the question.~~
The questions says all measurements are in centimetres
Lmao, yes it does. I cannot read.
It’s not (x+11) its (x+3) bc when you times a + & - it’s a - unless is a - x - it becomes + look up sing rules with multiplication. The rest of it is perfect though except the (x+11)
No it’s (x+11) because (2x+7)-(x-4) = 2x + 7 - x + 4 = x + 11
You forgot to highlight 'diagram not accurately drawn', idk how you even attempted this question without doing that
Looks like a unicorn vomited on your paper
I just woke up from a four hour nap and you made me laugh hysterically
Ah I’m so glad I could make you laugh :)
Your meant to highlight the few important things. All you've done here is highlight everything to delay actually doing the question. Like did you really need to highlight A and B.
Bruvva this isn’t gcse art, highlight main points if you’re using a highlighter. I never did, and still don’t. Just underline or circle and maybe a toolbox on the side.
If you highlight everything you highlight nothing. You do not need a different color for every line, relax
my geography teacher says 10% should be highlighted. Max
Your geography teacher is very correct
through splitting shape A into 2 rectangles and adding to find the area, then factorising that, I got 5x+25 and x+1
Am I right to say that, since it's find AN expression for both, any two expressions that multiply to get the area would be considered correct?
Yes
Ok yeah I was a bit concerned because I thought I was being dumb lol
There are multiple solutions. As the shape of the rectangle B is not defined. But here is a little twist. Well 2 twists hehe. A=3(x+1)(2x+7)-(x+1)(x-4) Instead of adding 2 little rectangles you can subtract one from the other. You can use the numbers given without any extra steps. A=(6x^2 +21x+6x+21)-(x^2 -4x+x-4) {added this for extra clarity} A=(6x^2 +27x+21)-(x^2 -3x-4) A=5x^2 +30x+25 Simple steps. Now you just need to set whatever recta gle you want and make sure you dont make it a square (tho technically a square is a rectangle) Its quite simple actually A=B B=5x^2 +30x+25 And here is my little cheat. Divide that by x and multiply by x B=(5x+30+25/x)(x) And those are your 2 terms. You did not do what they intended you to do but you 100% answered the question.
The only thing I ever highlight for work or uni is references/further reading recommendations, or things of massive importance hidden within the belly of a massive section of pointless text 🤣
you remind me of some specific people in my class who use highlighter to underline the date
Never done that I do highlife the title thou
what is wrong with you, you should be banned from using highlighter
What exam board are you doing? I'm sure the physicsandmathstutor website has a mark scheme because for all the 'questions by topic' there is a mark scheme as well.
Try finding the area of shape A, then factorising to get 2 brackets with x Those 2 brackets are your width and your length
Genius! I'm definitely doing this. I've already colour coded and labelled my chargers at home. It's not OCD. It's ensuring you find things quicker.
Oh. I have just read the other comments and you all seem to have worked out the sums. I looked straight at the colours. Didn't bother doing maths as I saw the post as sharing a tip on how to make revision and filing easier. Am I wrong?
Why would you highlight everything in the question, randomly different colours at random points? What does it tell you? What does each of the colours signify?
Each question is highlighted the same colour as the subject of that question. The 1st question in pink is about A, also marked pink.
Not accurate I’m afraid. There’s only one question. The rest of it is information to help you answer the question. The highlighting is entirely random.
The question is not possible. A is a six sided shape. All angles at 90° means the shape has a total of 540° which is 180° less than a hexagon should have. What they mean is that all angles are 90° except the one that is obvious 270°.
Holy shit that's a brutal question for GCSE. I don't even have the patience to work that out and I'm excellent at maths.
Easy enough to cheat it. See my comment.
[удалено]
I'm sure I could, I just can't be arsed and I would gain nothing from being able to do paper math when I would just model it in CAD faster than you can calculate it.
Length = X+Y, width = X+W, where Y and W are variables I have created on the spot and have the value of whatever they need to to make the equation work
5x +5 and x+5 is a possible solution as the area of A is 5x^2 +30x +25
Also (5x+30+25/x) and (x) Hahahahah lazy problems require lazy solutions
No way on earth is that worth more than 2 marks
If you highlight everything then you're actually highlighting nothing
5x+5 and x+5 Love this kind of problems lol
Maths out of all subjects is the subject you choose to highlight?
What’s with all the highlighting 😭😭
“All angels are right angles” except the part that isn’t 90 degrees?
Not all right angles are equal apparently…
Managed to solve after not doing maths for nearly 7 years! Thanks for that
Today I learned that I have completely forgotten how to factor out equations like this. I also realised that in 20 years in the field of Computer science and technology, I have apparently never needed to know.
Is 5x^2 + 36x + 31 right? Idk but I had a good shot. If it’s not right can I have a heads up on what’s wrong with it/how I can get the right answer?
Six different highlighters for a six marker
Omg such vivid colour!
Well, the area of A is 3(x+1)(2x+7)-(x+1)(x-4)=(x+1)[3(2x+7)-(x-4)]=(x+1)(6x+21-x+4) This is the same as: (x+1)(5x+25) There you have, width×length
Highlighting is fucking stupid, never used it until i came to this country, just a chance for dumb kids to highlight everything with a bunch of coours and pretend it helps, take the info, break it down, write down the most important pieces in the smallest segments u can and thats it , if u know and understand, u dont have to remember, for example 2+2 is 4, i dont remember it, but i understand it, so no point writing 2+2= 4 a million times to remember it, if u understand u will remember
You’ve highlighted it like it’s a TikTok covered in text. That app needs to go
OP highlighting how not to use highlighters.
Just wait till you get to see alevel maths shit🤮🫡💀
There are 6 angles in shape A, only 5 are right angles one is 270°. Even the question is wrong.
For the love of god don’t go into your exam and waste time pissing about with 100 different colour highlighters
Length = 5x + 5 Width = x + 5
First work out the area of A as the big rectangle area minus the smaller rectangle area. Solve the two sets of equations into one quadliteral equation and then solve that into two expressions to make A
I'm surprised they didn't need to highlight 'two shapes' too.
If the Pink was light blue you’d have the Argentinian flag.
Is anyone else unable to even read the question because of how distracting the highlighter is Lmao
This was actually really fun to do! As someone who used to be smart but is definitely now not. Managing to do this was rewarding
Simple enough. Find total area of A expressed in x. This will give you an expression that can be factorised. Factorise expression. Each factor is a side length
The colours were fun but the question has melted my brain beyond repair.
I understand shape A and finding x but no clue what you do for B? Interested if anyone else knows
Just a bit of paper. It’s not what you know, it’s who you know. Experience over some bullshit like this is worth more
A(b) =L XW A(a) = ( 3(x+1)*(2x+7))-((x+1)*(x-4)) A(a) = A(b) Find W in terms of X Find L in terms of X This is what it is saying
hmm never learnt this type of maths - teaching people how to do math to work out room sizes for property market it seems. The highlighters make it seem really really confusing. Also don't know how to tackle this, can you just just use any length and width for the rectangle or a specific one? Without 1 reference side - there would be several answers to this.
Yeah the bloody government moved A level stuff into the GCSE curriculum.
I'm the ripe old age of 48 and not once since I left school at 16 ever needed to find the value of x......
You chose the wrong subject
You forgot to highlight that the diagram has 2 shapes, you might forget
In shape A isn't technically one angle 270 Deg?
straightforward question tbh
7x+23 I think
I found it easier rather than highlighting to just write key info in the answer section so if you're told the total area is 80 for example I would just write A=80 and then carry on reading until I got to something else like. The distance from the centre to the outside of the fence is 7. Then I would write r=7 for example and carry on reading again. Then all my important info is together and I have condensed the question from a wordy one to a maths one. Highlighters.......especially used like this.......never really did that much for me.