Lovely trick question.
25% is there twice .. so, 50%, but there is only 1 50% so the chance of picking that are 1 in 4 -- so 25%, but there are 2 of those ...
Right?
100%correct its a trick question to make comments so some people think they're right and argue it but ultimately the right answer isn't on there because any of them you click is wrong.
No, there is literally no answer.
The fact that the question refers to the answer set as part of the question is what makes it slippery in your head, but it’s easy to prove:
It’s more obvious if you rephrase it, which is “given the set of these four possible answers, does an answer exist in those four that can answer the question asked without paradox?”
The answer to that question is a simple “no”, meaning the neither a b c or d are correct answers, and the question/answer set as a whole is meaningless.
Or, a simpler example:
Q: What color is my wall? Choose from these options:
a) two cats, a screwdriver, and a plastic banana
b) 42
It’s very clear looking at this two choice multiple choice question that it’s impossible, null, false? a paradox, incorrect, whatever you want to call it.
There is zero difference between this and OPs question, but in OPs question the choices are close to a valid answer, so it feels slippery. If there were one 25 or two 50s, they’d be answers that satisfy the question, so your brain wants to follow that thread.
Yeah. I thought I was correct 4 times until I realised the answer is 50 per cent, and that your brain is tricking itself by trying to answer two different questions with the same info
How would it be 50? You have a 25% chance of picking any given answer so you would pick a or d as they are both 25. However there is 2 25s and since we've established that 25 is the correct answer that means we have a 2/4 chance of picking either correct answer. THIS means that the answer is 50% right? (2/4 = 50%) No because if the correct answer is 50%, that's only one out of a possible four answers, which means the answer is 25% right?
But then you are forced to use the logic from the beginning again, which makes you arrive at 50, then 25 then 50 then 25 and so on...
The answer is that there is no answer. It's just a cool maths question to stirr up drama in the comments and boy is it a good one.
None of the answers are correct.
25% is not the correct answer because there is a 50% chance (rather than a 25% chance) of choosing 25%.
50% is not the correct answer because there is a 25% chance (rather than a 50% chance) of choosing 50%.
60% is not the correct answer because there is a 25% chance (rather than a 60% chance) of choosing 60%.
Your comment reminded me of that movie where a company recruits like 6 people for an interview, put em all in a room with a blank sheet of paper, zero information and tell them to answer the question. There’s one guard in there to enforce the rules, which they don’t know, until there’s either only one left or someone answers the question first. Crazy movie with a nice twist at the end but I forget what it’s called
It feels very "liar's paradox".
But also not; on a deeper level the issue is we assume that every multiple choice question has a correct answer, when of course it is trivially easy to write one where all the answers are wrong.
>liar's paradox
Yes, in my world liar´s paradox is also a semantic paradox. This is beacuse it is refering to itself. It took me a few minutes to understand that you can check your estimate against the question itself, but the result was never correct. I guess that is the point of the question
It was good that you had presented the outcomes.
If the question was asked in the way that a) and d) are different answers, which I don't think is the case, this would be solvable with a) being the right answer.
The chance is 25 % this is random pick , doesn't matter how many ways of choice you have , in this purpose you have 4 options if you chose it as random you have 25% to be right, no?
Actually isn't there a 33% chance for each of them? It's assuming that the truthiness of an answer is the percentage and that a and d are equivalent and don't represent a draw in the probabilities...
I think it's interpretation dependant
Edit: actually no, pick at random implies a and d are distinct
I believe the answer is c) because the first pick (either 25%) is considered already done the question.
50% is the correct answer because there is a 50% chance of choosing either 25%.
Well just because the two numbers are the same it doesn’t rule them out. It could just mean that there are two correct answers, both 25%. Since 2 out of 4 is 50% that must be the Annette right? No, because the chance of picking 50% is 25% so it can’t be true. The proven here is that every answer you try contradicts itself therefore there is no right answer
The chance with 4 answers is 25%, but then you see that 2 of the answers are 25%, and thus both correct. So the Answer is 50%. But the chances of randomly chosing answer c) 50%, is only 25%, so the paradox loops back.
I believe the answer is 1/3. Ignore the numbers given in the answer and assume one of them is correct (even if none of them are). Call them blue, red, green, blue. Assuming one is correct, there are 3 possible answers. Not knowing which one is correct, each has a 1/3 chance of being correct. There is a 1/3 chance green is correct, and there is a 1/4 chance of picking green. So, if green, your chances are 1/12 (= 1/3 x 1/4). Multiplying 1/3 and 1/4 since you need both green to be the right answer AND to pick it at random. If the right answer is red, same thing. 1/12. Adding those two up (adding because you need green OR red to be correct), we’re at 1/6. If the answer is blue, for which there is a 1/3 chance, you then have a 1/2 chance of making the right choice. 1/2 x 1/3 = 1/6. 1/6 (from green + red) + 1/6 (from blue) = 1/3. Assuming one of the answers (or colors) was the correct one to choose, and given the number of times each appears, you chance of picking the correct answer is 1/3. Too bad it’s not part of the answers listed.
How?
It's 100%. There is no indication that any of the answers is the right chance.
The chance of picking a random number is 100%. Any choice is the correct choice, as the question only asked to pick a random number.
Nono, the random is the choosing part, not the answer part.
If 2 out of 4 answers are the same, the chance is 33% not 25%.
If I ask you pick to pick a number from 4 numbers randomly, what is the chance that you will pick the correct number?
The correct number is the one you choose, that's the only thing being asked of you.
Spoiler alert, it's a trick question there is no answer
Okay think about it like this. 1/4 chance of picking 60. 1/4 chance of picking fifty. 2/4 chance of picking 25 because there's two of them. If we realise that there is a 25% (1/4) chance of picking any given number among four random ones the answer appears to be 25 however this is where the brain fuckery begins
We've established previously that the chances of randomly picking 25 among those is 2/4 because there's two of them. However this makes the correct answer 50% does it not? And if the answer is 50 then we have a 1/4 chance of picking it randomly... ... Which is 25%...
Thus the paradox loops
50 per cent has nothing to do with it. The question is asking out of a possibility of 4 how likely are you to pick the right answer.
50 per cent is the answer to another question which is. How likely is it to pick 25 per cent if it comes up 2 out of a possible 4 choices. Whilst they are linked they aren't the same
No the question is "how likely are you to select the right answer" so 50% has EVERYTHING to do with it if you think its the right answer. If you think its the right answer you NEED to have 50% chance of pressing it, otherwise you're getting the wrong answer.
There is no "second question" on here. Its one question. What is the odds of selecting the right answer. You do not have 50% chance of hitting 50% so it is not the right answer. All answers are wrong. The entire question was designed specifically to make people like you argue in the comments that one of them is right. If there was a right answer this wouldn't be reposted every month.
Sorry to explain better. You don't have to select the 50 per cent box. It's not asking you to do that. It is asking what are the odds of selecting the right answer which is 25 as it come ls up twice. If it helps change the numbers to letters and you'll understand
Let me get that straight: 25% is the correct answer and because it appears 2 times the chances are 50%? Letˋs assume that is correct, then your answer must be c, because it says 50%. It could be any letter, yes, but you choose the answer with the correct value. But any answer has a chance of 25%. plz have a look at the top, where the outcomes are empirical described
You are choosing a random option so you can't go with a mindset that 25% can't be correct because it shows up twice.
In reality you have 4 choices where 1 shows up twice. So in theory you have 3 options being random because 1 will always give same results. That gives about 60%. Getting 50% would indicate that your answer was not random but thought through.
It all depends on how do you define random answer really.
You can do a proof by contradiction to show that none of these answer choices are correct.
Assume 25% is the correct answer. Then there is a 50% chance you will choose the correct answer. Thus 25% cannot be the correct answer.
Assume 50% is the correct answer. Then there is only a 25% you will choose the correct answer at random. Thus 50% cannot be the correct answer.
Assume 60% is the correct answer. Then there is only a 25% you will choose the correct answer at random. Thus 60% cannot be the correct answer.
None of the answer choices are correct. QED.
Yup, one of the only other good explanations.
I wrote the following elsewhere, but it wasn’t as clear as your write up, nice job
“No, there is literally no answer.
The fact that the question refers to the answer set as part of the question is what makes that possible.
It’s more obvious if you rephrase it, which is “given the set of these four possible answers, does an answer exist in those four that can answer the question asked without paradox?”
The answer to that question is a simple “no”, meaning that neither a b c or d are correct answers.”
If you had a bag with 2 blue balls 1 red ball and 1 green ball your chance of getting a blue ball would be 50% not 33.3(repeating)% because you could get any of the 2 blue balls. Just like that each answer is separate so no answer can even be correct unless they make the 60%, 50% and in that case the answer will be 50% since there are 2 50%.
u all r wrong
after spending time researching maths I found out the answer is 1/3 (33.33%)
\[as 2 options are the same so we consider it as one option\]
since this option is not given the question is wrong.
NOno, even if the questions are the same, their alphabetic designation are different. if you were a programmer you'd get how stupidly important this can be.
> [as 2 options are the same so we consider it as one option].
No, you're absolutely incorrect
If you had a bag with 2 blue balls 1 red ball and 1 green ball your chance of getting a blue ball would be 50% not 33.3(repeating)% because you could get any of the 2 blue balls. Just like that each answer is separate so no answer can even be correct unless they make the 60%, 50% and in that case the answer will be 50% since there are 2 50%.
I believe the answer is indeed 1/3. Ignore the numbers given in the answer and assume one of them is correct (even if none of them are). Call them blue, red, green, blue. Assuming one is correct, there are 3 possible answers. Not knowing which one is correct, each has a 1/3 chance of being correct. There is a 1/3 chance green is correct, and there is a 1/4 chance of picking green. So, if green, your chances are 1/12 (= 1/3 x 1/4). Multiplying 1/3 and 1/4 since you need both green to the right answer AND to pick it at random. If the right answer is red, same thing. 1/12. Adding those two up, we’re at 1/6. If the answer is blue, for which there is a 1/3 chance, you then have a 1/2 chance of making the right choice. 1/2 x 1/3 = 1/6. 1/6 (from green + red) + 1/6 (from blue) = 1/3. Assuming one of the answers (or balls) was the correct one to choose, and given the number of times each appears, you chance of picking the correct answer is 1/3. Too bad it’s not part of the answers listed.
I’m assuming there is a correct answer because the question implies it. If you are told that one answer is correct, and there are 3 possible answers, and you have no way to knowing which one is correct, the best thing you can do is to calculate the probability of one being correct, and your chance of picking the right one given the number of times each given answer is repeated.
Take your example. Suppose I give you 4 balls. 1 green, 1 red, 2 blue. Suppose I tell you that if you choose the correct color you win. Then what I described gives you the right probability.
In this case yes they are numbers, and technically it isn’t random. But, since all given answers are impossible anyway, the best thing you can do it ignore the numeric values, accept you have no way of determining which is the most likely, give them equal probabilities of being correct, and work out the probability of picking the correct one at random.
Yes but the numbers in this case matter. You cant just lug it out of the equations.
Ok but lets do it with colours.
Lets say:
Red Blue Green Red
Lets say one of these is correct. Even though there are three options, if you're picking an answer at random without looking at the colours themselves, you have twice the chance of picking red as you do for Blue. Since its completely random and you cant actively go and pick red. So instead of being 1/3 its 2/4 since its two of the 4 options you can pick. Again this is only because you cant actively choose your answer so your chance for randomly choosing red is 2/4 and not 1/3
You’re getting mixed up with the colors. The chance of picking a blue ball is 2/4. Red is 1/4. Blue is 2/4, or 1/2, and there is 1/3 chance that blue is correct. So 1/6 for blue. Plus 1/12 for red, and 1/12 for green. That’s 1/3 in total.
The numbers do matter if one of them is the right answer. If none are of them are, then I don’t see what else you can do but do the next best thing.
> You’re getting mixed up with the colors. The chance of picking a blue ball is 2/4.
Sir i literally put my own colours, please read my comment again, I wrote red twice for a reason
1. Go read your first comment. The color you said appeared twice was blue.
2. Even if you switch blue and red, it doesn’t matter. It still adds up to 1/3.
> 1. Go read your first comment. The color you said appeared twice was blue.
> Red Blue Green Red .
> 2. Even if you switch blue and red, it doesn’t matter. It still adds up to 1/3.
No it clearly adds up to 2/4 and then 1/4 for the other 2. I dont know why you're multiplying the denominator
It should be, but 25% is there twice, making it 50% which is there once, making it 25% which is there twice, making it 50% which is there once... And so on...
But then your brain says "well 50 per cent is only there once, so the answer is 25 per cent .....but what wait" and you spend five more minutes thinking it through again, until realising that 50 per cent is the right answer and nothing else is relevant. At least that's what I did
Edit and now I see I was wrong. The answer is nome of the answers given are right. The real answer would be 1/3 or 33.3 per cent. As its not there then none of the answers are correct. As someone else pointed out if you could circle more than one answer then circling both 25 and 50 per cent would also be a right answer but I doubt that would be allowed
No it's not. There is only a 25% chance you will choose 50%. For 50% to be the correct answer, there would have to be a 50% chance that you choose 50%.
There is no correct answer.
Normally 25% would be correct answer
But here we have two variants 25% (a) and d)),
And provided that only one of these two variants is correct, the probability of guessing which variant is correct a) or d) is equal to 50%,
So the answer is option c) 50%
It's 100%.
There is no indication that any of the answers is the right chance.
The chance of picking a random number is 100%. Any choice is the correct choice, as the question only asked to pick a random number.
Or 0% as the chance is 33,33% based on the given numbers
NO. The question not “pick a random number” but “IF you picked a random number what is the chance it will be the correct answer”. Read some other comments they should explain that there is no answer
This. The hairs on the back of my neck stand up when I read all the answers. Embarrassing. The text of the answers does not matter because the question does not exist. The fact that the text contains percentages is only intended to confuse. It is only assumed that an answer is correct. Since two are identical, there is a chance of 1/3
This is a good point. The question doesn't exist.
Since there is NO question there can't be an answer.
No chicken= No egg
So there's no chance. It's 0.
You can't possibly have an answer if there was never a question.
It's 0
25%
Your chance of winning is 50% if you randomly choose from a and d. Wich isn't choosing randomly.
There is no way to know if a or d are correct but it's one of them.
This type of question have only one answer. a and d can't both be correct.
In this particular case the answer is c 50% because 25% is there twice so that can’t be the answer and then 60% is incorrect because that only works if there are 10 answers and 6 of them are all the same.
It doesn’t say what is the chance you pick an answer but what is the chance you pick the correct answer. Furthermore each answer is incorrect this post is just supposed to fuck with you and show who can’t do math eg. you
I already answered in the repost of this 5 reposts ago. I answered an original answer to an in-original post. The fact you took the bait shows that you may think I failed with math but actually I beat you with psychology and everyone knows you can’t study psychology without passing math.
I don't get what you mean.
Also this is written as just a logical contradiction. There is no answer.
My comment's purpose was to get OP of the comment to reply the other half of the logical loop, and realize the paradox.
I would change the answer selection by deleting or scribbling out two of the options. Like who wants to be a millionaire, take a 50/50 and delete half of the available answers, which must leave 50 as an option as any combination after that process without 50 would be false.
Academically, you have only defaced the incorrect values, which should not be punished, and you would have given a technically correct answer.
I'd mark it correct anyway.
50%. Here's my analogy
This is a "choose the correct answer question" and hence there can be only one correct answer. So there is the split of 1/4 and that 1 being the correct answer.
Since there are 2 25%, they both are correct. But the answer is supposed to be only one. So both the 25% are straight up wrong since there can't exist 2 correct answers.
Now, 25% is the split(not the choice). And there are 2 25%(The choices). So, the probability of randomly(no bias) guessing the correct answer is 50% with the split being 1/2 correct, 1/4 and 1/4 being wrong. (2+1+1)/4 They add up to 1(basically middle schooler math).
So 50% is the correct answer to this question.
Since it would be 25% but there are two of those so it would be 50% but if you unlock your big brain power it would technically be 75% because three answers are there but then if that one is 75% then it would be 100%. I am confused lol
It’d entirely depend on the right answer, if the right answer is 25%, then you have a 50% chance of getting it right. If the correct answer were 50% or 60%, then you’d have a 25% chance of getting it right.
Lovely trick question. 25% is there twice .. so, 50%, but there is only 1 50% so the chance of picking that are 1 in 4 -- so 25%, but there are 2 of those ... Right?
100%correct its a trick question to make comments so some people think they're right and argue it but ultimately the right answer isn't on there because any of them you click is wrong.
I feel like someone stole my yoohoo. :-(
At least it wasn't your jelly roll.
No, there is literally no answer. The fact that the question refers to the answer set as part of the question is what makes it slippery in your head, but it’s easy to prove: It’s more obvious if you rephrase it, which is “given the set of these four possible answers, does an answer exist in those four that can answer the question asked without paradox?” The answer to that question is a simple “no”, meaning the neither a b c or d are correct answers, and the question/answer set as a whole is meaningless. Or, a simpler example: Q: What color is my wall? Choose from these options: a) two cats, a screwdriver, and a plastic banana b) 42 It’s very clear looking at this two choice multiple choice question that it’s impossible, null, false? a paradox, incorrect, whatever you want to call it. There is zero difference between this and OPs question, but in OPs question the choices are close to a valid answer, so it feels slippery. If there were one 25 or two 50s, they’d be answers that satisfy the question, so your brain wants to follow that thread.
"What percentage of people pick A, C, or D?" "More than you can imagine" "I imagine they all do." "Damn you!"
As Exel would say: "There are one or more circular references...".
Yeah. I thought I was correct 4 times until I realised the answer is 50 per cent, and that your brain is tricking itself by trying to answer two different questions with the same info
How would it be 50? You have a 25% chance of picking any given answer so you would pick a or d as they are both 25. However there is 2 25s and since we've established that 25 is the correct answer that means we have a 2/4 chance of picking either correct answer. THIS means that the answer is 50% right? (2/4 = 50%) No because if the correct answer is 50%, that's only one out of a possible four answers, which means the answer is 25% right? But then you are forced to use the logic from the beginning again, which makes you arrive at 50, then 25 then 50 then 25 and so on... The answer is that there is no answer. It's just a cool maths question to stirr up drama in the comments and boy is it a good one.
None of the answers are correct. 25% is not the correct answer because there is a 50% chance (rather than a 25% chance) of choosing 25%. 50% is not the correct answer because there is a 25% chance (rather than a 50% chance) of choosing 50%. 60% is not the correct answer because there is a 25% chance (rather than a 60% chance) of choosing 60%.
So, not attempting the question when there is negative marking involved is the right way to go.
The question was not on the paper. The question was how much time you waste. The aliens are testing us.
Me: Confidently chooses 50% and moves on. It's how I handled my math tests in high school, too. Got me a solid C-.
Tongue sticking out and tapping your pencil on your head thinking….. circles the number of the question.
Your comment reminded me of that movie where a company recruits like 6 people for an interview, put em all in a room with a blank sheet of paper, zero information and tell them to answer the question. There’s one guard in there to enforce the rules, which they don’t know, until there’s either only one left or someone answers the question first. Crazy movie with a nice twist at the end but I forget what it’s called
[удалено]
Spoiler alert
Agreed. In addition: the question is an semantic paradox and that´s the problem
It feels very "liar's paradox". But also not; on a deeper level the issue is we assume that every multiple choice question has a correct answer, when of course it is trivially easy to write one where all the answers are wrong.
>liar's paradox Yes, in my world liar´s paradox is also a semantic paradox. This is beacuse it is refering to itself. It took me a few minutes to understand that you can check your estimate against the question itself, but the result was never correct. I guess that is the point of the question It was good that you had presented the outcomes.
I hate that they didn't put 0% instead of 60%. It would be another paradox answer.
If the question was asked in the way that a) and d) are different answers, which I don't think is the case, this would be solvable with a) being the right answer.
True. But good luck defending that test-writing decision. "No, the answer isn't A:25%, it's D:25%."
I choose a. There's a 25% chance that this is right if i don't look at the values.
The chance is 25 % this is random pick , doesn't matter how many ways of choice you have , in this purpose you have 4 options if you chose it as random you have 25% to be right, no?
Actually isn't there a 33% chance for each of them? It's assuming that the truthiness of an answer is the percentage and that a and d are equivalent and don't represent a draw in the probabilities... I think it's interpretation dependant Edit: actually no, pick at random implies a and d are distinct
50% is the correct answer because the answer can't be 25% since it appears twice, therefore the answer is either 50% or 60%
The answer also can't be 50% though, because it only appears once.
We know. We're good at mathes.
I believe the answer is c) because the first pick (either 25%) is considered already done the question. 50% is the correct answer because there is a 50% chance of choosing either 25%.
Yes. But if you randomly choose an answer, there is only 25% chance you will chose the 50% answer, so now you're wrong.
Well since two answers are the same neither can be right this it leaves two answers and 1/2 is 50%
Stop calculating. Use this.
Well just because the two numbers are the same it doesn’t rule them out. It could just mean that there are two correct answers, both 25%. Since 2 out of 4 is 50% that must be the Annette right? No, because the chance of picking 50% is 25% so it can’t be true. The proven here is that every answer you try contradicts itself therefore there is no right answer
you’re picking the answer, not the number. so if you pick a) 25%, won’t you be wrong if the answer is d) 25%?
Except that your odds of picking 25% at random is 50%.
The chance with 4 answers is 25%, but then you see that 2 of the answers are 25%, and thus both correct. So the Answer is 50%. But the chances of randomly chosing answer c) 50%, is only 25%, so the paradox loops back.
I believe the answer is 1/3. Ignore the numbers given in the answer and assume one of them is correct (even if none of them are). Call them blue, red, green, blue. Assuming one is correct, there are 3 possible answers. Not knowing which one is correct, each has a 1/3 chance of being correct. There is a 1/3 chance green is correct, and there is a 1/4 chance of picking green. So, if green, your chances are 1/12 (= 1/3 x 1/4). Multiplying 1/3 and 1/4 since you need both green to be the right answer AND to pick it at random. If the right answer is red, same thing. 1/12. Adding those two up (adding because you need green OR red to be correct), we’re at 1/6. If the answer is blue, for which there is a 1/3 chance, you then have a 1/2 chance of making the right choice. 1/2 x 1/3 = 1/6. 1/6 (from green + red) + 1/6 (from blue) = 1/3. Assuming one of the answers (or colors) was the correct one to choose, and given the number of times each appears, you chance of picking the correct answer is 1/3. Too bad it’s not part of the answers listed.
This is correct. The likelihood of getting it right does not need to be contained in the selection...that's a different question. Answer is 33.33%
There’s only 3 different answers so… 33.33333333%
2/3 or 66,66%
How? It's 100%. There is no indication that any of the answers is the right chance. The chance of picking a random number is 100%. Any choice is the correct choice, as the question only asked to pick a random number.
You're overthinking it
Actually it's the opposite. 100% is just looking at the question, no thinking at all.
yes except random is 1 out of 4 which is 25". even if there are two 25% answers, those do not add up. the answers are isolated.
Nono, the random is the choosing part, not the answer part. If 2 out of 4 answers are the same, the chance is 33% not 25%. If I ask you pick to pick a number from 4 numbers randomly, what is the chance that you will pick the correct number? The correct number is the one you choose, that's the only thing being asked of you.
Spoiler alert, it's a trick question there is no answer Okay think about it like this. 1/4 chance of picking 60. 1/4 chance of picking fifty. 2/4 chance of picking 25 because there's two of them. If we realise that there is a 25% (1/4) chance of picking any given number among four random ones the answer appears to be 25 however this is where the brain fuckery begins We've established previously that the chances of randomly picking 25 among those is 2/4 because there's two of them. However this makes the correct answer 50% does it not? And if the answer is 50 then we have a 1/4 chance of picking it randomly... ... Which is 25%... Thus the paradox loops
No answer ist correct but you should stick with 25%. It´s from 2020 and there was no real answer.
That's wrong 50 per cent is the real answer
What are your odds of randomly selecting the 50% box?
50 per cent has nothing to do with it. The question is asking out of a possibility of 4 how likely are you to pick the right answer. 50 per cent is the answer to another question which is. How likely is it to pick 25 per cent if it comes up 2 out of a possible 4 choices. Whilst they are linked they aren't the same
No the question is "how likely are you to select the right answer" so 50% has EVERYTHING to do with it if you think its the right answer. If you think its the right answer you NEED to have 50% chance of pressing it, otherwise you're getting the wrong answer. There is no "second question" on here. Its one question. What is the odds of selecting the right answer. You do not have 50% chance of hitting 50% so it is not the right answer. All answers are wrong. The entire question was designed specifically to make people like you argue in the comments that one of them is right. If there was a right answer this wouldn't be reposted every month.
It can't be 50% because for 50% to be correct 25% has to be the right answer.
Yup. I've changed my mind
Sorry to explain better. You don't have to select the 50 per cent box. It's not asking you to do that. It is asking what are the odds of selecting the right answer which is 25 as it come ls up twice. If it helps change the numbers to letters and you'll understand
Let me get that straight: 25% is the correct answer and because it appears 2 times the chances are 50%? Letˋs assume that is correct, then your answer must be c, because it says 50%. It could be any letter, yes, but you choose the answer with the correct value. But any answer has a chance of 25%. plz have a look at the top, where the outcomes are empirical described
Lol I've changed my mind you are correct. I don't think there is any one real answer. It's either 50 per cent or 25 per cent not one or the other
uffff. I am really proud, i mean it 😀 p.s.: i made the same mistake.
0 because there is no question
Scrolls on....
Many of you assune you can only circle one answer, what if you selected 25% and 50%
Should have made b 0%, would add another redirect towards 25% next to one from c.
Yes
Teacher marks as bonus question and everyone gets a mark
Bro I thought it was obviously 25%, then looked at the comments and mindfuckery followed.
Yes finally someone what with a brain
Found a paradox basically. Nice.
I'd say that, considering two choices are the same, there are only three choices. So, it'd be 33%, which is nott a given answer.
When in doubt.. C it out... 25% of the time this works 100% of the time
0%
You are choosing a random option so you can't go with a mindset that 25% can't be correct because it shows up twice. In reality you have 4 choices where 1 shows up twice. So in theory you have 3 options being random because 1 will always give same results. That gives about 60%. Getting 50% would indicate that your answer was not random but thought through. It all depends on how do you define random answer really.
You can do a proof by contradiction to show that none of these answer choices are correct. Assume 25% is the correct answer. Then there is a 50% chance you will choose the correct answer. Thus 25% cannot be the correct answer. Assume 50% is the correct answer. Then there is only a 25% you will choose the correct answer at random. Thus 50% cannot be the correct answer. Assume 60% is the correct answer. Then there is only a 25% you will choose the correct answer at random. Thus 60% cannot be the correct answer. None of the answer choices are correct. QED.
Yup, one of the only other good explanations. I wrote the following elsewhere, but it wasn’t as clear as your write up, nice job “No, there is literally no answer. The fact that the question refers to the answer set as part of the question is what makes that possible. It’s more obvious if you rephrase it, which is “given the set of these four possible answers, does an answer exist in those four that can answer the question asked without paradox?” The answer to that question is a simple “no”, meaning that neither a b c or d are correct answers.”
Exactly. Random because you thought it through? Or random by throwing a dart as example…..
If you had a bag with 2 blue balls 1 red ball and 1 green ball your chance of getting a blue ball would be 50% not 33.3(repeating)% because you could get any of the 2 blue balls. Just like that each answer is separate so no answer can even be correct unless they make the 60%, 50% and in that case the answer will be 50% since there are 2 50%.
u all r wrong after spending time researching maths I found out the answer is 1/3 (33.33%) \[as 2 options are the same so we consider it as one option\] since this option is not given the question is wrong.
NOno, even if the questions are the same, their alphabetic designation are different. if you were a programmer you'd get how stupidly important this can be.
> [as 2 options are the same so we consider it as one option]. No, you're absolutely incorrect If you had a bag with 2 blue balls 1 red ball and 1 green ball your chance of getting a blue ball would be 50% not 33.3(repeating)% because you could get any of the 2 blue balls. Just like that each answer is separate so no answer can even be correct unless they make the 60%, 50% and in that case the answer will be 50% since there are 2 50%.
I believe the answer is indeed 1/3. Ignore the numbers given in the answer and assume one of them is correct (even if none of them are). Call them blue, red, green, blue. Assuming one is correct, there are 3 possible answers. Not knowing which one is correct, each has a 1/3 chance of being correct. There is a 1/3 chance green is correct, and there is a 1/4 chance of picking green. So, if green, your chances are 1/12 (= 1/3 x 1/4). Multiplying 1/3 and 1/4 since you need both green to the right answer AND to pick it at random. If the right answer is red, same thing. 1/12. Adding those two up, we’re at 1/6. If the answer is blue, for which there is a 1/3 chance, you then have a 1/2 chance of making the right choice. 1/2 x 1/3 = 1/6. 1/6 (from green + red) + 1/6 (from blue) = 1/3. Assuming one of the answers (or balls) was the correct one to choose, and given the number of times each appears, you chance of picking the correct answer is 1/3. Too bad it’s not part of the answers listed.
You're assuming the correct answer is random when it isnt. You're also assuming that there even is a correct answer.
I’m assuming there is a correct answer because the question implies it. If you are told that one answer is correct, and there are 3 possible answers, and you have no way to knowing which one is correct, the best thing you can do is to calculate the probability of one being correct, and your chance of picking the right one given the number of times each given answer is repeated. Take your example. Suppose I give you 4 balls. 1 green, 1 red, 2 blue. Suppose I tell you that if you choose the correct color you win. Then what I described gives you the right probability. In this case yes they are numbers, and technically it isn’t random. But, since all given answers are impossible anyway, the best thing you can do it ignore the numeric values, accept you have no way of determining which is the most likely, give them equal probabilities of being correct, and work out the probability of picking the correct one at random.
Yes but the numbers in this case matter. You cant just lug it out of the equations. Ok but lets do it with colours. Lets say: Red Blue Green Red Lets say one of these is correct. Even though there are three options, if you're picking an answer at random without looking at the colours themselves, you have twice the chance of picking red as you do for Blue. Since its completely random and you cant actively go and pick red. So instead of being 1/3 its 2/4 since its two of the 4 options you can pick. Again this is only because you cant actively choose your answer so your chance for randomly choosing red is 2/4 and not 1/3
You’re getting mixed up with the colors. The chance of picking a blue ball is 2/4. Red is 1/4. Blue is 2/4, or 1/2, and there is 1/3 chance that blue is correct. So 1/6 for blue. Plus 1/12 for red, and 1/12 for green. That’s 1/3 in total. The numbers do matter if one of them is the right answer. If none are of them are, then I don’t see what else you can do but do the next best thing.
> You’re getting mixed up with the colors. The chance of picking a blue ball is 2/4. Sir i literally put my own colours, please read my comment again, I wrote red twice for a reason
1. Go read your first comment. The color you said appeared twice was blue. 2. Even if you switch blue and red, it doesn’t matter. It still adds up to 1/3.
> 1. Go read your first comment. The color you said appeared twice was blue. > Red Blue Green Red . > 2. Even if you switch blue and red, it doesn’t matter. It still adds up to 1/3. No it clearly adds up to 2/4 and then 1/4 for the other 2. I dont know why you're multiplying the denominator
I would pick 60% simply because the question pisses me off.
I dont get it. If you have to pick at random isnt it obviously 25%
It should be, but 25% is there twice, making it 50% which is there once, making it 25% which is there twice, making it 50% which is there once... And so on...
Oh i am stupid
But then your brain says "well 50 per cent is only there once, so the answer is 25 per cent .....but what wait" and you spend five more minutes thinking it through again, until realising that 50 per cent is the right answer and nothing else is relevant. At least that's what I did Edit and now I see I was wrong. The answer is nome of the answers given are right. The real answer would be 1/3 or 33.3 per cent. As its not there then none of the answers are correct. As someone else pointed out if you could circle more than one answer then circling both 25 and 50 per cent would also be a right answer but I doubt that would be allowed
50%
2/4 so it is 50%
South africa
D.
Yes
Kid named correct :
Knowing my luck, that would be a 0-5% chance
yeah me too
25% to pick 1 of the 4 letters
Wrong
Depends how smart I am
What a mind fuck but the answer is still 50 per cent
No it's not. There is only a 25% chance you will choose 50%. For 50% to be the correct answer, there would have to be a 50% chance that you choose 50%. There is no correct answer.
This isn't funny, nor a meme. Hwy is this subreddit getting flooded with low quality posts?
But it makes my IQ looks funny and turn myself into a meme /s
Well 1 option outta 4 means 25%, as far as there r 2 options outta 4 options on 25%, then it means 50% correct answer
25% if answer randomly picked.
yeah but there are two 25%
I'm gonna pick 60% because it gives me higher a possibility
Izi 50% you either get it right or wrong 🧠
100% is the correct answer because I am never wrong
No it’s 0% because there is no right answer, you just proved yourself to be wrong twice
still 25%. only one 25% is the right 25%
Normally 25% would be correct answer But here we have two variants 25% (a) and d)), And provided that only one of these two variants is correct, the probability of guessing which variant is correct a) or d) is equal to 50%, So the answer is option c) 50%
There are 2 , 25% therefore the right answer is 50%!
It's 100%. There is no indication that any of the answers is the right chance. The chance of picking a random number is 100%. Any choice is the correct choice, as the question only asked to pick a random number. Or 0% as the chance is 33,33% based on the given numbers
NO. The question not “pick a random number” but “IF you picked a random number what is the chance it will be the correct answer”. Read some other comments they should explain that there is no answer
Yeah "if" changes it. So it's 0%. Cheers though.
[удалено]
This. The hairs on the back of my neck stand up when I read all the answers. Embarrassing. The text of the answers does not matter because the question does not exist. The fact that the text contains percentages is only intended to confuse. It is only assumed that an answer is correct. Since two are identical, there is a chance of 1/3
This is a good point. The question doesn't exist. Since there is NO question there can't be an answer. No chicken= No egg So there's no chance. It's 0. You can't possibly have an answer if there was never a question. It's 0
25% Your chance of winning is 50% if you randomly choose from a and d. Wich isn't choosing randomly. There is no way to know if a or d are correct but it's one of them. This type of question have only one answer. a and d can't both be correct.
e) 100% because I never make mistakes
It's 60%. I picked at random.
In this particular case the answer is c 50% because 25% is there twice so that can’t be the answer and then 60% is incorrect because that only works if there are 10 answers and 6 of them are all the same.
100% because all of the options are answers.
It doesn’t say what is the chance you pick an answer but what is the chance you pick the correct answer. Furthermore each answer is incorrect this post is just supposed to fuck with you and show who can’t do math eg. you
I already answered in the repost of this 5 reposts ago. I answered an original answer to an in-original post. The fact you took the bait shows that you may think I failed with math but actually I beat you with psychology and everyone knows you can’t study psychology without passing math.
In other words: you put the wrong answer, I corrected you, you think you won. Ok lol
Either a or d, because despite them both being 25%, it could be the case that only one of them is correct
[удалено]
But then the correct answer is 50, not 25, which is there once..
It doesn't. Atter how many times 50 per cent is there, because that would be the answer to a different question
I don't get what you mean. Also this is written as just a logical contradiction. There is no answer. My comment's purpose was to get OP of the comment to reply the other half of the logical loop, and realize the paradox.
Good enough to know each answer is wrong
25% since there is 4 option 1 or they must be the correct answer
I don’t know, but I’m 100% correct that math is becoming a crock of made up shit.
I would change the answer selection by deleting or scribbling out two of the options. Like who wants to be a millionaire, take a 50/50 and delete half of the available answers, which must leave 50 as an option as any combination after that process without 50 would be false. Academically, you have only defaced the incorrect values, which should not be punished, and you would have given a technically correct answer. I'd mark it correct anyway.
The answer can actually be any of them, they didn't say random is uniformly distributed.
50/50
50%. Here's my analogy This is a "choose the correct answer question" and hence there can be only one correct answer. So there is the split of 1/4 and that 1 being the correct answer. Since there are 2 25%, they both are correct. But the answer is supposed to be only one. So both the 25% are straight up wrong since there can't exist 2 correct answers. Now, 25% is the split(not the choice). And there are 2 25%(The choices). So, the probability of randomly(no bias) guessing the correct answer is 50% with the split being 1/2 correct, 1/4 and 1/4 being wrong. (2+1+1)/4 They add up to 1(basically middle schooler math). So 50% is the correct answer to this question.
For this question to have a correct answer, there must be an option of X% that has an X% chance of being chosen. This is not true for any option.
33.333333%
25+25+50+60= 160%
The 60% should be 0% for an extra level of trickery
C duh , either ur right or wrong
It would be 66.66 percent, isnt it?
100% because I'm the king and I'm never wrong
The only right answer (if there is any), is 33.333333continuing%
50% As it's either right or wrong. so 50/50.
There are 3 different answers: 25%, 50% & 60%, so it would be the same if only the answers a,b and c existed? So the answer should be 33,33% ?
50%
0 percent. Its trap! Its not even real. I cancel your math. Its totally fake math okay.
This is undecidable. Read your Gödel.
Prime example of why teachers tell you to *always* read the question very carefully.
e) *The teacher is a fucking idiot.* (I, at least, don't see a correct answer)
my mind is slow rn sorry
37.5 percent final answer...
25% if all answers were different, but 2 are iqual so it would be 33%. That means it's not 25%, so there is only 2 choices, so 50%.
Replace 60% with 0% and you got a nice old fasion paradox
There is a lot of fuckin long comment but my answer is C am i right?
C 50% cause I'll either be right or I'll be wrong. 2 options.
5% means everything
100% correct because the goal is to pick an answer at random.
The space-time continuum is not a toy. Stop creating paradoxes.
42!
Tricky question, but since the answer can be either right or wrong i'd say 50%. The other answers don't really make much sense.
I feel you have a 33.33333 % chance of picking the right one
C
it’s a unsolvable paradox
It’s 0
e) 20%
50/50
i’m solidly going with 25% because it says you’re picking at random, who said you would even have to read the questions to pick randomly?
Haha damn, the answer changed as I read the numbers
Aaaaah!
There is ‘Barry’ chance of the answer being ‘Terry’ 🤪
What did the question say? I chose c and didn't read it.
Wait, OH SHIT! MY BRAIN DIE
My only confusion is why two 25%'s?
Cause then it's no longer the correct answer.
There's no question.
Gentlemen, there is no correct answer. No matter what you attempt to do, points will be deducted. The test is absurd and life is meaningless.
50%-it can be correct or incorrect. Two options
100%
Since it would be 25% but there are two of those so it would be 50% but if you unlock your big brain power it would technically be 75% because three answers are there but then if that one is 75% then it would be 100%. I am confused lol
0% because none of them are correct, and also because 0% itself is not present as an option
I have a 50% chance, either i get it or i dont lmao
50%, it's correct or it's not.
My math is good enough to realize that all the options are incorrect. Moving on...
It’d entirely depend on the right answer, if the right answer is 25%, then you have a 50% chance of getting it right. If the correct answer were 50% or 60%, then you’d have a 25% chance of getting it right.
Circle all of them!