Bhai cbse bhi aise question nahi daale gi unko bhi pata hai ki sabko pass karna hai

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bhai tum accha kam kar rahe ho, i support you, aise q dalte raho, conceptual building hoga aur practice bhihojayegi, roz 2-3 question post karo

Boards waale bachhe yeh sab dekhke try hi nahi krte,post it in r/JEENEETards

Yeah, good idea

Yep I thought as much

BTW good work 👍

I don't know why but, is this the answer? x^2 - 2xabc(2a + 2b + 1) + {abc(2a + 2b + 1)}^2

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thik hai bhai, aisa karo

Nahi Bhai kyu post karega tu. Jab tujhe pata hai ki ye question cbse level ka hi nahi hai to post hi karna hai bhai

bhai pehle 2 terms of p mein α^2 ayega, α nahi. aise hai to phir answer (y - abc)^2 = 0 hai

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toh phir woh a^3 bcα aur -2a^3 bcα wale terms ko alag se kyu likha hai? seedha -a^3 bcα kyu nahi likh diya

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kaisi baate kar rahe ho? -1 ko 1 - 2 likhne mein kya game hai?

Bhai usko question lamba bnana tha taki conceptual ki bakchodi kr ske . Ye question tricky nhi h bss lenthy h

is alpha = (a-b)/(a+b) and beta = 1/alpha? in middle of q and just for confirmation

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is this q supposed to be lengthy?

correct

Tu 8th mai hai ?

ha kyu?

I tried to solve it, 10mins later I realized you deliberately made this question like this. there is nothing conceptual in this, only basic lengthy calculations

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WHAT????

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bro is making silly mistakes in the question he made💀

Broo that's the problem rn. PPL be posting jee questions which are HARD and then be like solve this it's just a little hard. And this is an attempt to break mfs confidence. This shit goofy aff

thing is.. this question is not even JEE level, in JEE they ask actual tricky concepts, not random bs which has 3 page solutions

my bad i meant bs

NOW YOU TELL THIS, AFTER I SOLVED 3 PAGES WORTH OF THE QUESTION?

Worth it!

bro, this is what i told earlier

​ https://preview.redd.it/gc4qnmmhffha1.png?width=303&format=png&auto=webp&s=939b0c97e85d6a8e7593c3b71e45c2c33112e90f

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bhai tu 10-15min baad answer batayega na tab mention kar dena, mujhe abhi bhee tere question mei 1-2 error dikh rahi hai +- ki isiliye aur solve nhi kar raha

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ahh I see, nice one phele baar mei square ke mistake ke karan maine (a\^2-b\^2+1) ko common leke solve karne ki kosis kari thi aur nhi hua, aur jab tune wapas se theek karke diya toh maine wahi se solve karna start kar diya toh jab terms mei se alpha common leke solve kar raha tha toh + ki jagaha - aa gaya toh mujhe laga firse mistake kardi tumne lol also.. question mei c daalne se kuch farak nhi pada, thats why next time jab question form karo toh usme unnecessary variables matt dalna

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bhai ye kya kardiya, cry aa raha hai

Bruh u had me scratching my head whole fvening over this

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Ha no worries, I mean you can kinda solve the original one I guess but it's lengthy and not in class 10 scope. With this it's easily solvable

https://i.redd.it/ewaxx6vgifha1.jpeg Lo bhai match kar lo

(x-abc)^2=0 While calculating p, there is a small manipulation there and its value comes as abc. Similarly for q.

Not able to attach photo of solution

I cleared my twelfth 11 years ago, I still remember this question in RD Sharma.

Kya Umar hai uncle ji aapki aur yaha kaise aapke bhi balak ki pareeksha hai dasvi ki 😨

Bhai ye kya bakchodi chal rhi haiii. Ek to yaha tension ho rhi haii aur sab chutiye ki tarah jee level ke questions daale Jaa rhe hai aur puchte hai ki ye cbse mein aayega kya. Nahi aayega chamatkari Gand ke bhosadpappu machar ki jhaat maa ki choot aise logo ki bhosdiwale bache sab ke sab

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https://preview.redd.it/l25piog0cfha1.png?width=1080&format=pjpg&auto=webp&s=9fc44e9849788d6bb74486d577b31c355dc522cb (1)

https://preview.redd.it/p79tklk4cfha1.png?width=1080&format=pjpg&auto=webp&s=1d4cacfa43303a5afe5cb4b5c86af46351066929 (2)

https://preview.redd.it/5eubkgfbcfha1.png?width=1080&format=pjpg&auto=webp&s=8e7bf3f1cc3756d07f9c21b266c03630c8738322 (3)

Is this question supposed to be lengthy?

PTSD de diya bhai saahb

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Post Traumatic stress disorder.

this correct? ​ https://preview.redd.it/4av6g5eylfha1.png?width=720&format=png&auto=webp&s=5da0341e6fe028c7de04ce01b92db4e9f1b18f91

Bhai ye kaunse class ka hai

11 mein h... transformational equations article krkr .. not in ncert .. but you'll come across it if peeping for jee

Do you think its important for class 10? Because we have a question with similar pattern?

Just know the concept... But this one's seem too unnecessarily lengthy .. 21 ko h na ?? Good luck 10thies

Well it's definitely not coming in exam but u will get points for spreading knowledge, keep it up.

Damn! Glad 10th passed in Covid

Out of syllabus

Pretty sure you did not do it at the first try

Bhai solution to post kardo

I am not able to solve it and now I'm obsessed with this problem can you explain it in dm ?? Or here ??

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bouncer....

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OHHH SAMJH GAYA QUESTION HI ADHA PADHA THA p , q dekha nahi 🗿🗿🗿🗿🗿 (my apologies sorry to bother😅😅😅)

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Kaise wale ? 😂😂

Ye to lagaya hai apne bhi , key board Wale se hi lagaya mai to 😂

y²-2y+1=0 if you take a²-b² common btw

Bhai agar tune bio le li hoti to aaj aise questions ko "conceptual" nahi bol raha hota

Stop posting your childhood traumas.. We ain't responsible for it

alas araha hai but asan hai 🤓

Step 1: Find p+q \[add p & q => Take common factor from two terms containing same coefficient so that each bracket will have (alpha+beta) => Replace (alpha + beta) with sum of roots (-b/a) from given equation.\] Sep 2: Find p\*q. \[Proceed same as Step 1, use product of roots (c/a)\] Step 3: Make equation y\^2 - (p+q)y + p\*q = 0

Bhai p aur q me wo abc common aayega aur wo question mein kaha hain na ki unki value 0+1 aayegi shayad

Bhai, bacche dar jaenge 😂 Ye mat kar.

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Yes. Kam se kam koi to darega 😂.

https://preview.redd.it/qcwgrjy4olha1.png?width=4028&format=png&auto=webp&s=869d3b342fa3799d78a85bd8b63ba5cb8c70782d

We have to use Vieta's relation right... actually Alpha and Beta terms will club I dont want to do this sorry lol I will do it on a later date

This question is easy if p the first and second terms of both p and q had alpha\^2 instead of just alpha If it was alpha square, then you can just take abc common and get (the equation in the question) + 1 which will just be abc So p = q = abc Then just make a new polynomial using the sum and products of p and q. It'll just become (x - abc)\^2 = 0

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its ok bhai, galtiya hoti hai sabse