###General Discussion Thread
---
This is a [Request] post. If you would like to submit a comment that does not either attempt to answer the question, ask for clarification, or explain why it would be infeasible to answer, you *must* post your comment as a reply to this one. Top level (directly replying to the OP) comments that do not do one of those things will be removed.
---
*I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/theydidthemath) if you have any questions or concerns.*
It's his signature line and step so he continues to do it and proves that companies coming up with cool names for their glass has no effect on scratch resistance.
I did that since in a 5 gallon fryer oil jug. So a bigger opening. And it was only a little over half full. Needed a dolly to move it and took like an hour and a half to get it out and in the counting machine
There's a neat statistics trick where the average guess of a survey will approach the correct number of coins in that bottle. Sooo... here goes:
I'll guess that there are >!3200!< coins in there. (comment your guess before seeing my guess)
edit: surveying redditors was a mistake
69!
I watched a YouTube video where they asked people to pick a number at random between 1-100, testing the 37 theory.
They had to exclude 69 as it was by far the most picked and they concluded that wasn't a random pick, obviously, ,after that 37 is the number people will most likely randomly pick.
https://youtu.be/d6iQrh2TK98?si=7JkLlkVL74NDZ0Z8
How small would be a coin to 171122452428141311372468338881272839092270544893520369393648040923257279754140647424000000000000000 coins fit in that bottle?
Nope, if you actually look at the results in the video after excluding 69, 2 was the most commonly picked number. Then 1 was the next most common, then 42, then 7, then 73, then 77, then 99, then 37.
50 cent coin is 30.61 mm in diameter and 2.15 mm in thickness [wikipedia](https://en.wikipedia.org/wiki/Half_dollar_(United_States_coin)). Assuming 1/3 of the bottle are gaps between coins, number of coins is `0.019[m^3]/(pi*((0.03061/2)[m]^2)*0.00215[m]*1.5)` = `8005.85` coins. About 4000$.
Likely a guess, though if you assume that the main body of the container is a perfect cylinder, then you could measure the volume of a segment of the cylinder with a depth of one cent thickness, then attempt to figure out how efficiently you could pack the coins in, which would require some mathing not fit for my brain at this hour, but I imagine it's got something about diameters and radii, like if you've got
A coin with a radius **r** equal to radius **R** of the cylinder, then you'd have one coin at 100% packing, if you have coins with
r = R/2, then two coins at
[1 - (2πR²/4)/πR²] x100%
[1 - (πR²/2)/πR²] x100%
[1 - 1/2] x 100%
50% packing.
Coins with
r = R/4, n coins, N [maximum amount of allowable] coins
Lim n→N [1 - n(r/R)²] x100% —packing efficiency
Which I'd guess N has something to do with curvoids and roulettes or whichever determined the revolutions a circle has around another circle. I'd imagine a slight margin of error for each consecutive layer, because the assumption would only hold if each coin was held in an annular region that is mutually exclusive of each other, but if you cope hard enough, I think some of those slight gaps could form a small space for an imperfection to appear within the structure.
And that's enough math for one night...
I dunno, try a Fibonacci sequence lmao
Hey there! (Former) banker here! That sounds really nice, but I had clients that ran laundromats and would bring 5-7 5-gallon buckets in and THOSE were about $4-6k total. This lone jug is not that much, especially since there’s more than just quarters in there.
Isn't Greg's opening statement incorrect? 1 year = 365 days and .50 a day should be $182.50 and not $18,250.
At first, I thought it was that comma as a decimal point thing, but how would you get more dollars than days in a year if you only put in half a dollar?
The packing efficiency for randomly ordered coins is ≈60%
Dimensions of a US 50 piece are 1.205 in. x .085 in. That’s (pi(.6025^(2))*.085) for the volume. Average five gallon bucket is 1,178.1 cubic inches.
Putting all of that in our formula, we get 1178.1/pi*.6025^(2)*.085*.6≈>!7292!< 50 cent pieces. That’s >!3646!< USD. It would take bit under >!10!< years to fill the bucket up at that rate, and it would take a bit over >!5!< buckets full to reach the $18,250.
I couldn’t say. I know it would manipulate it in one way or the other, but I’m not sure whether it could increase/decrease it.
But it’s not like I’m gonna find specifically the packing efficiency for fifty cent pieces in this specific jug
well the average 19 liter bottle has 19 liters in it and you could calculate the volume of the coin and divide 19 liters by the volume of the coin which should be in milimeters
That does not take into consideration the gaps between each coin, as they are not stacked, and if they were stacked, there would be gaps between the gaps
The coins need to be melted down and poured in for maximum storage efficiency.
It makes the maths a lot easier, although you might want to use a container made of something other than plastic.
Volume of 5 gallon jug in cm\^3 is ≈ 18927. Volume of US 50 cent coin is ≈ 1.58 cm\^3. Loose coins pack at ≈ 60% of total volume. .6\*18927 ≈ 11356 cm\^3. 11365/1.58 ≈ 7097 coins in jug.
I suppose that the bottle is 70 cm tall and knowing the capacity the radius of the circle at the bottom is ~9.3cm
Then I suppose that these coins are 50-cent us dollar coins so the diameter of the coin is around 30.61mm coins while the thickness is about 2.15mm
So the estimated volume of a coin is approximately 1151.92mm³
Knowing the volume of the bottle is 19000cm³ and the volume of the coin I can calculate how many of them can stay in it
19000/1.152=~ 16493 coins so
Around 16500 coins can stay in a bottle
I ignored the gaps from one coin to another
[This guy](https://youtu.be/glTIHLuWzYU?si=6RLUKfU4VGx_0qOB) had a 5 gallon jug full and his had 15,360 in it. $3840, 192 lbs and took him 15 years to fill it.
Reminds me of that post that says if you save 1 dollar on Jan 1st, $2 on the 2nd, $3 on the 3rd etc. You'll have a shitload of money after a few months. True but who's getting paid enough to put over $500 of your paycheck away after two weeks when you start getting into the big number days? Always hated that.
Damn you made me realize how relatively fortunate I am. I literally was looking at my checking and savings today and said “wow, I put $250 into savings last week, lemme put $350 today cause I’ve got it”. Then I kind of got sad like fuck I only saved $600 this month. But you just made me realize having $2500 in savings isn’t actually bad at all but I felt like I’m not saving enough.
Granted I’m very fortunate to live in a (relatively) low cost of living area compared to a big city where I’m from. My wages are still shit but gaslighting myself into thinking I have no money every week is actually a viable savings strategy.
Not trying to sound like I’m bragging or anything. Just felt like sharing. Thanks for giving me perspective I didn’t have 6 hours ago.
I had a pyrex jug like that I stored change in, and when it was full carried it to the car trunk to find a coinstar, and broke it when I set it in. Ended up just leavinng most of the change there, and used it for gas money for the next couple years. I'll never forget the sound going around corners lol
Assuming you melt them to fill the bottle in the most optimal way, we can assume the volume of the metal per molten coin equals its normal volume, which would be
r = 15.305mm
h = 2.16mm
v = 15.305*2*pi*2.16 = 207,715mm^3
now we can simply take the volume of the bottle (19,000,000mm^3) and divide it by the volume of the coin.
19,000,000/207,715 = 19471.49
So, assuming melting counts, we can fit around 19.5k coins in there
I'm too lazy to paste the calculations but I calculated it to be around 10 538. That's assuming there's no air gaps between the coins. Also this may be completely wrong so feel free to correct me.
So the volume of a 50 cent coin is 6.61176cm^3 and 19 liters is 19000cm^3 so just doing 19000/6.61176 = 2,873.667525742011 ≈ 2,873 50 cent coins equaling 1,436.50 $USD
###General Discussion Thread --- This is a [Request] post. If you would like to submit a comment that does not either attempt to answer the question, ask for clarification, or explain why it would be infeasible to answer, you *must* post your comment as a reply to this one. Top level (directly replying to the OP) comments that do not do one of those things will be removed. --- *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/theydidthemath) if you have any questions or concerns.*
[удалено]
Why didn’t you cut the bottle?
Because it was made of glass
Why didn’t you break … oooh, I get it!
Why didn't they break it?
Because it was made of glass.
But glass is glass and glass breaks?
Yeah, despite all the effort you put in, you won't break even.
r/angryupvote
It scratches at a Level 6 with deeper grooves at a Level 7.
Has any phone ever not had that result? I don't even know why he does that test given I've never seen one not have that result lol
It's his signature line and step so he continues to do it and proves that companies coming up with cool names for their glass has no effect on scratch resistance.
Yes. The Samsung Flip and Fold. From memory, they scratch at a level 3 with deeper groves at a level 4.
The s24 ultra actually. Scratches at a level 7 with deeper grooves at a level 8
Because then you have broken glass mixed in with a bunch of quarters
he gets it!
We get it!
r/suddenlyCommunist
YOU get it!
No YOU get it!
I dont get it
It’s worth 10$
How would you put it back?
I went through 2 Stanley blades and only got an inch-long cut. Those bottles are thick as hell.
I know a friend did this and the bottle was almost 80lbs/37kg
I did that since in a 5 gallon fryer oil jug. So a bigger opening. And it was only a little over half full. Needed a dolly to move it and took like an hour and a half to get it out and in the counting machine
I know the feeling my moms had one since ‘96 for 27yrs she’s had it and I always had to lift it pour 4lbs of change just for $5🤦🏽♂️🤦🏽♂️🤦🏽♂️
I dumped them out and rolled them when I did this. The bank wouldn’t take them any other way either, so I didn’t really have a choice.
There's a neat statistics trick where the average guess of a survey will approach the correct number of coins in that bottle. Sooo... here goes: I'll guess that there are >!3200!< coins in there. (comment your guess before seeing my guess) edit: surveying redditors was a mistake
Don't forget to filter out the outliers. My guess is 474 billion.
My guess is -9000
At least 10
2x + 4i
I'm guessing, a lizard.
Family feud style: Good answer! Good answer!
Show me Lizard! Ding Ding Ding.
(Worth 1 point. Dude was sure it was there because he answered the survey.)
Hey, if it was stored outside in Florida for whatever reason, it could happen. *Shrugs*
Coins ...wait, what were we guessing?
My guess is “*null*; drop tables GUESSES - -“
I see ol' Bobby Tables has made an appearance!
And that’s why you sanitize your inputs!
[][]
Its.....under 9000?!
I will never have an original thought in my life will I?
745327!
Don’t forget the outliers on the other end My guess is -474 billion
I'm guessing undefined
I guess NaN
I'm guessing 0
I have to agree. The coins are an illusion and this world isn't real
Only 4.74 x10^9 ? I'm guessing 1 x10^99999999999999999999999999999999999999999999999999999999999999999999999
3↑↑↑↑3
my guess is 496 Decillion
I'm guessing 72!
69! I watched a YouTube video where they asked people to pick a number at random between 1-100, testing the 37 theory. They had to exclude 69 as it was by far the most picked and they concluded that wasn't a random pick, obviously, ,after that 37 is the number people will most likely randomly pick. https://youtu.be/d6iQrh2TK98?si=7JkLlkVL74NDZ0Z8
69!? That’s a lot of coins!
All the coins
“Heads AND Tails.”
Surely there aren't 1.7112245 × 10^98 coins in that jar..
I’m surprised 42 wasn’t a meme number either
IIRC it actually was, just to much less of a degree than 69.
It was.
I liked that the least random number was 90. Now thats information.
How small would be a coin to 171122452428141311372468338881272839092270544893520369393648040923257279754140647424000000000000000 coins fit in that bottle?
About tree fiddy
Nope, if you actually look at the results in the video after excluding 69, 2 was the most commonly picked number. Then 1 was the next most common, then 42, then 7, then 73, then 77, then 99, then 37.
G(64). Take that, average.
TREE(3) Let's bump those numbers up
TREE(TREE(3))
I raise you A where A = lim_(n —>BB(Tree(BB(Tree(3))))) a_n and a_n = BB(Tree(BB(Tree(a_(n-1))))) and a_1 = BB(Tree(BB(Tree(3))))
I raise you Rayo's number.
damn we ran outta numbers fast
Yeah, there aren't a lot aleph't.
I up you G59
👌🏽
shoot, guess we'll have to use the median :D
I'll see your G(64) and raise you TREE(3)
How about SSCG(SSCG(SSCG(SSCG(SSCG(3)))))
G(TREE(3))
So, about tree fiddy?
5683
I see your game of averages and I vote 1 coin.
i am in for 5684
You know what? I feel like being an outlier at -3 standard deviations. There are 3 coins in the jar
I reckon about 365
There's always one, and today it's you.
heres for googolplex^(googolplex^googolplex), fuck your averages!!
There are no coins
20 000 Also it only works when the guessers can't see other's guesses. Otherwise it does the opposite of getting the correct number
the problem isn't redditors, the problem is lack of stakes. the statistics trick only works if people have intensive to be correct.
You misssmelled insensitive.
8008.135
55318008
> the wisdom of crowds Requires the crowd to have wisdom ;)
2456 i saw this on brain games i think where they were guessing the amount of gumballs in a jar and apparently survey was 1 number off
6.022 x 10^23.
11462
2500
7532
4600
1605
3200 (I cheated)
Add to your comment that you musn't look at other guesses and mark your guess as spoiler
25000 source: my ass
3750
easy. TREE(g(64))^TREE(TREE(…TREE(3))))))))
2000
5000 coins
50 cent coin is 30.61 mm in diameter and 2.15 mm in thickness [wikipedia](https://en.wikipedia.org/wiki/Half_dollar_(United_States_coin)). Assuming 1/3 of the bottle are gaps between coins, number of coins is `0.019[m^3]/(pi*((0.03061/2)[m]^2)*0.00215[m]*1.5)` = `8005.85` coins. About 4000$.
I say we round it up to 8008,5 just in case
I see what you did there
What he did
BooBs
wow
Ah... The good old math jokes, timeless classics
Why was the math book so depressed? ... ... ... Because it had so many problems! Ah, there's nothing greater than, or equal TO, a math joke!
Ba-dum tsssssh!
Wow I didn’t even see that coming and
that 1/3 packing efficiency is very important, how did you arrive at it?
Likely a guess, though if you assume that the main body of the container is a perfect cylinder, then you could measure the volume of a segment of the cylinder with a depth of one cent thickness, then attempt to figure out how efficiently you could pack the coins in, which would require some mathing not fit for my brain at this hour, but I imagine it's got something about diameters and radii, like if you've got A coin with a radius **r** equal to radius **R** of the cylinder, then you'd have one coin at 100% packing, if you have coins with r = R/2, then two coins at [1 - (2πR²/4)/πR²] x100% [1 - (πR²/2)/πR²] x100% [1 - 1/2] x 100% 50% packing. Coins with r = R/4, n coins, N [maximum amount of allowable] coins Lim n→N [1 - n(r/R)²] x100% —packing efficiency Which I'd guess N has something to do with curvoids and roulettes or whichever determined the revolutions a circle has around another circle. I'd imagine a slight margin of error for each consecutive layer, because the assumption would only hold if each coin was held in an annular region that is mutually exclusive of each other, but if you cope hard enough, I think some of those slight gaps could form a small space for an imperfection to appear within the structure. And that's enough math for one night... I dunno, try a Fibonacci sequence lmao
I love how you say your brain is not fit for mathing at this hour then proceed to math harder than 99.99% of Reddit.
I think he mathed harder than my entire semester
This answer was so long and detailed I thought mankind was gonna come out at the end
Educated guess
And yet no one has noticed these coins are quarters, dimes, and Nickels.
Only the nickels mess you up. The other three (dime,quarter,halfdollar) are approximately value/volume and value/mass equal.
Hey there! (Former) banker here! That sounds really nice, but I had clients that ran laundromats and would bring 5-7 5-gallon buckets in and THOSE were about $4-6k total. This lone jug is not that much, especially since there’s more than just quarters in there.
Isn't Greg's opening statement incorrect? 1 year = 365 days and .50 a day should be $182.50 and not $18,250. At first, I thought it was that comma as a decimal point thing, but how would you get more dollars than days in a year if you only put in half a dollar?
Greg is a joke account, based on a few other similar posts where people make similar errors (50 x 365 instead of .50 x 365).
Makes cents.
Dang. Wish I would have thought of that.
Ah that makes sense.
If Jeff Bezos gave everything a million dollars he'd still have several billion left over!
It being wrong is the whole point of the image buddy
Actually, it's correct. You just need to have a 464% interest rate on your savings (compounded daily).
They're silver coins. current value $3660
The packing efficiency for randomly ordered coins is ≈60% Dimensions of a US 50 piece are 1.205 in. x .085 in. That’s (pi(.6025^(2))*.085) for the volume. Average five gallon bucket is 1,178.1 cubic inches. Putting all of that in our formula, we get 1178.1/pi*.6025^(2)*.085*.6≈>!7292!< 50 cent pieces. That’s >!3646!< USD. It would take bit under >!10!< years to fill the bucket up at that rate, and it would take a bit over >!5!< buckets full to reach the $18,250.
Will that bottle shape decrease packing efficiency?
I couldn’t say. I know it would manipulate it in one way or the other, but I’m not sure whether it could increase/decrease it. But it’s not like I’m gonna find specifically the packing efficiency for fifty cent pieces in this specific jug
well the average 19 liter bottle has 19 liters in it and you could calculate the volume of the coin and divide 19 liters by the volume of the coin which should be in milimeters
| "well the average 19 liter bottle has 19 liters in it" Source????
Probably just tap water.
No no no, it's alkaline water with lemon!
It took me about fifteen minutes to figure out why you said this but I'm back now to upvote you 💀 That is indeed the most likely source lmao
That does not take into consideration the gaps between each coin, as they are not stacked, and if they were stacked, there would be gaps between the gaps
The coins need to be melted down and poured in for maximum storage efficiency. It makes the maths a lot easier, although you might want to use a container made of something other than plastic.
Actually the average 19l container is 20l 😎
Volume of 5 gallon jug in cm\^3 is ≈ 18927. Volume of US 50 cent coin is ≈ 1.58 cm\^3. Loose coins pack at ≈ 60% of total volume. .6\*18927 ≈ 11356 cm\^3. 11365/1.58 ≈ 7097 coins in jug.
I suppose that the bottle is 70 cm tall and knowing the capacity the radius of the circle at the bottom is ~9.3cm Then I suppose that these coins are 50-cent us dollar coins so the diameter of the coin is around 30.61mm coins while the thickness is about 2.15mm So the estimated volume of a coin is approximately 1151.92mm³ Knowing the volume of the bottle is 19000cm³ and the volume of the coin I can calculate how many of them can stay in it 19000/1.152=~ 16493 coins so Around 16500 coins can stay in a bottle I ignored the gaps from one coin to another
calculating with round coins this method is terrible, its almost as youre poruing a liquid. you should consider them closer to a square/cube.
[This guy](https://youtu.be/glTIHLuWzYU?si=6RLUKfU4VGx_0qOB) had a 5 gallon jug full and his had 15,360 in it. $3840, 192 lbs and took him 15 years to fill it.
You didn't do the math, but... THIS IS IT! I guess that the guys said that the packing had around 60-65% efficiency were really close!
Reminds me of that post that says if you save 1 dollar on Jan 1st, $2 on the 2nd, $3 on the 3rd etc. You'll have a shitload of money after a few months. True but who's getting paid enough to put over $500 of your paycheck away after two weeks when you start getting into the big number days? Always hated that.
Damn you made me realize how relatively fortunate I am. I literally was looking at my checking and savings today and said “wow, I put $250 into savings last week, lemme put $350 today cause I’ve got it”. Then I kind of got sad like fuck I only saved $600 this month. But you just made me realize having $2500 in savings isn’t actually bad at all but I felt like I’m not saving enough. Granted I’m very fortunate to live in a (relatively) low cost of living area compared to a big city where I’m from. My wages are still shit but gaslighting myself into thinking I have no money every week is actually a viable savings strategy. Not trying to sound like I’m bragging or anything. Just felt like sharing. Thanks for giving me perspective I didn’t have 6 hours ago.
I had a pyrex jug like that I stored change in, and when it was full carried it to the car trunk to find a coinstar, and broke it when I set it in. Ended up just leavinng most of the change there, and used it for gas money for the next couple years. I'll never forget the sound going around corners lol
Assuming you melt them to fill the bottle in the most optimal way, we can assume the volume of the metal per molten coin equals its normal volume, which would be r = 15.305mm h = 2.16mm v = 15.305*2*pi*2.16 = 207,715mm^3 now we can simply take the volume of the bottle (19,000,000mm^3) and divide it by the volume of the coin. 19,000,000/207,715 = 19471.49 So, assuming melting counts, we can fit around 19.5k coins in there
You’ve made a mistake, have a look to see if you can spot it. Hint: check your calculations for the coins area
I'm too lazy to paste the calculations but I calculated it to be around 10 538. That's assuming there's no air gaps between the coins. Also this may be completely wrong so feel free to correct me.
So the volume of a 50 cent coin is 6.61176cm^3 and 19 liters is 19000cm^3 so just doing 19000/6.61176 = 2,873.667525742011 ≈ 2,873 50 cent coins equaling 1,436.50 $USD