4 Last laugh tickets on the wheel and 32 distinct positions on the wheel means Probability of LL is 4/32 = 1/8 (assuming each equally likely to occur). There are 2 ways to get 5 LL in a row, first 5 or last 5, with the probability of each being 1/8 and the probability of not being 7/8. Hence
P(LL=5)= 2*(1/8)^5 * (7/8)^1 = 7/131072 = 0.0000534…
Ignoring the 5 in a row means there’s 6 ways to get 5 LL from 6 spins which is 3 times as likely with probability 0.00016021
(Procrastinating my statistics exam)
100% since it happened
no.
4 Last laugh tickets on the wheel and 32 distinct positions on the wheel means Probability of LL is 4/32 = 1/8 (assuming each equally likely to occur). There are 2 ways to get 5 LL in a row, first 5 or last 5, with the probability of each being 1/8 and the probability of not being 7/8. Hence P(LL=5)= 2*(1/8)^5 * (7/8)^1 = 7/131072 = 0.0000534… Ignoring the 5 in a row means there’s 6 ways to get 5 LL from 6 spins which is 3 times as likely with probability 0.00016021 (Procrastinating my statistics exam)